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7nadin3 [17]
2 years ago
12

The _____ has an oxygen atom single-bonded to hydrogen and single-bonded to a carbon-containing group.

Chemistry
1 answer:
Andrew [12]2 years ago
6 0

The alcohol has an oxygen atom single-bonded to hydrogen and single-bonded to a carbon-containing group.

<h3>What is alcohol? </h3>

Alcohol is defined as the organic compound which is derived from an hydrocarbon by replacing one hydrogen by hydroxyl group(—OH).

The general formula of alcohol is ROH.

where, R is the alkyl group.

The first member of alcohol is ethanol.

<h3>Physical properties of alcohol</h3>
  • Alcohols are colourless.
  • They give a sweet smell except for glycerol and few lower alcohols.
  • They are flammable and produce a blue flame on burning.
  • They don't produce any kind of smoke while burning.
  • Alcohol are liquid at room temperature.

Thus, alcohol is an organic compound which contain an oxygen atom which is single-bonded to hydrogen and single-bonded to a carbon-containing group.

learn more about alcohol:

brainly.com/question/22875792

#SPJ4

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phytoplankton, large shark, zooplankton, large fish, small fish

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Hope this helps!

did the quiz and got 100%

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6 0
3 years ago
Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t
Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)

Now we have to calculate the amount of heat released or absorbed in both processes.

<u>For process 1 :</u>

Q_1=m\times \Delta H_{fusion}

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Q_1 = amount of heat absorbed = ?

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Now put all the given values in Q_1, we get:

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<u>For process 2 :</u>

Q_2=m\times c_{p,l}\times (T_{final}-T_{initial})

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Now put all the given values in Q_2, we get:

Q_2=1.0Kg\times 4186J/Kg^oC\times (100-0)^oC

Q_2=4.186\times 10^5J

From this we conclude that, Q_1 that means it takes less amount of heat to metal 1.0 Kg of ice.

Hence, the it takes less amount of heat to metal 1.0 Kg of ice.

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