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I am Lyosha [343]
3 years ago
8

What do scientist do to easily share measurement data they can understand

Chemistry
1 answer:
Jobisdone [24]3 years ago
3 0
1. They use the same measuring system (metric)

2. Clearly and properly collect and record data, recording the procedure and results

3. Releasing the data into the public, letting everyone have access to it

maybe, I don't know what answer your teacher wants
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it depends upon the material used to make the brick

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I looked this up but hope it helps
7 0
3 years ago
In an exothermic reaction, energy is transferred from
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4 0
3 years ago
Compared to the freezing point of 1.0 M KCl(aq) at standard pressure, the freezing point of 1.0 M CaCl2(aq) at standard pressure
Galina-37 [17]

Answer : The correct option is, (1) lower

Explanation :

Formula used for lowering in freezing point :

\Delta T_f=i\times k_f\times m

where,

\DeltaT_b = change in freezing point

k_b = freezing point constant

m = molality

i = Van't Hoff factor

According to the question, we conclude that the molality of the given solutions are the same. So, the freezing point depends only on the Van't Hoff factor.

Now we have to calculate the Van't Hoff factor for the given solutions.

(a) The dissociation of KCl will be,

KCl\rightarrow K^++Cl^-

So, Van't Hoff factor = Number of solute particles = 1 + 1 = 2

(b) The dissociation of CaCl_2 will be,

CaCl_2\rightarrow Ca^{2+}+2Cl^-

So, Van't Hoff factor = Number of solute particles = 1 + 2 = 3

The freezing point depends only on the Van't Hoff factor. That means higher the Van't Hoff factor, lower will be the freezing point and vice-versa.

Thus, compared to the freezing point of 1.0 M KCl(aq) at standard pressure, the freezing point of 1.0 M CaCl_2(aq) at standard pressure is lower.

4 0
3 years ago
Calcium carbonate (caco3) is an important component of coral reefs. how many moles are in 98.6 g of caco3? type in your answer u
vovangra [49]

0.986 moles of CaO are formed when  98.60 g of CaCO_3decomposes.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 ×10^{23} of some chemical unit, be it atoms, molecules, ions, or others.

Number of moles of CaCO3 =\frac{mass}{molar \;mass}

Number of moles of CaCO3 = \frac{98.60 g}{100 g/mol}

= 0.986 moles

Reaction:

CaCO_3   →  CaO + CO_2

Since the reaction is 1:1:1.

So 0.986 moles of CaO are formed.

Learn more about moles here:

brainly.com/question/26416088

#SPJ1

7 0
2 years ago
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