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marshall27 [118]
3 years ago
7

Is marble a compound or element?​

Chemistry
2 answers:
Vesna [10]3 years ago
7 0

Answer:

compound

Explanation:

"Marble is typically more than 95% calcium carbonate, perhaps even 99% calcium carbonate, and calcium carbonate is a compound. Marble has a good claim to be recognized as a compound."

vekshin13 years ago
6 0

Answer: Element

Explanation: No, marble is not a compound, because for a rock to be called marble other characteristics, beyond the chemical composition, have to have specific values. But marble is made up of only one compound, calcium carbonate. Colored marbles do contain small amounts of other chemicals.

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The primary difference between a scientific theory and a hypothesis is that a theory is
Firlakuza [10]
A theory is a well-tested explanation <span>that uses a broad range of observations.</span> A hypotheses is an explanation for something, but the information is taken from observation, but has not been proved. Most hypotheses can be proven or disproven by further research.
7 0
3 years ago
At a certain temperature, the solubility of strontium arsenate, sr3(aso4)2, is 0.0590 g/l. what is the ksp of this salt at this
qaws [65]
First, we have to change Sr3(ASO4)2 from 0.059 g/L to moles:

and when the molar mass of Sr3(ASO4)2 = 87.6*3 + 74.9*2 + 16*8
                                                                      = 540.6 g/mol

Molarity (X) = 0.059 g/L * 1 mol / 540.6 g/mol
                    = 1.1 x 10^-4 moles 

When the solubility equation is:

Sr3(ASO4)2 ↔ 3Sr++(aq)   +  2ASO-3(aq)

so, Ksp = [Sr++]^3[ASO-3]^2

from ICE table and the balanced equation:
 [Sr++] = 3 X
           = 3* 1.1 x 10^-4 = 3.3x10^-4 M
 [ASO-3] = 2X
               = 2* 1.1 x 10^-4 = 2.2 x 10^-4 M

So, by substitution:

∴Ksp = (3.3 x 10^-4)^3 * (2.2 x 10^-4) ^2
       = 1.74 x 10^-18
       
8 0
3 years ago
Laboratory equipment is cleaned and properly stored after use primarily so that
kiruha [24]

Options are provided in the given question, so the complete question is as follows:

Laboratory equipment is cleaned and properly stored after use primarily so that —

A. chemical products can be measured and recorded as data

B. time is saved in setting up the next experiment

C. toxic materials can be kept in the laboratory

D. the possibility of contamination in the laboratory is minimized

Answer:

D. the possibility of contamination in the laboratory is minimized

Explanation:

After the completion of experiments, all the laboratory equipment should be cleaned and properly stored to minimize the possibility of contamination in the laboratory.

Any contamination in the laboratory can affect the experiment and will not give an accurate result, so it is important to clean and store the equipment properly.

Hence, the correct answer is "D".

4 0
3 years ago
TRUE or FALSE: The Periodic table is full of periodic trends and patterns.<br> True<br> False
anyanavicka [17]

Answer: false

Explanation:

6 0
3 years ago
V2O5 + Ca = V + CaO balance the eqaution
andreyandreev [35.5K]

Answer: The balanced equation is V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO.

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, V_{2}O_{5} + Ca \rightarrow V + CaO

Here, number of atoms on reactant side are as follows.

  • V = 2
  • O = 5
  • Ca = 1

The number of atoms on product side are as follows.

  • V = 1
  • O = 1
  • Ca = 1

In order to balance this equation, multiply Ca by 5 on reactant side. Multiply V by 2 and CaO by 5 on product side. Therefore, the equation can be rewritten as follows.

V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO

Now here, number of atoms on reactant side are as follows.

  • V = 2
  • O = 5
  • Ca = 5

The number of atoms on product side are as follows.

  • V = 2
  • O = 5
  • Ca = 5

Since, there are same number of atoms on both reactant and product side. So, the equation is now balanced.

Thus, we can conclude that the balanced equation is V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO.

5 0
3 years ago
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