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marshall27 [118]
3 years ago
7

Is marble a compound or element?​

Chemistry
2 answers:
Vesna [10]3 years ago
7 0

Answer:

compound

Explanation:

"Marble is typically more than 95% calcium carbonate, perhaps even 99% calcium carbonate, and calcium carbonate is a compound. Marble has a good claim to be recognized as a compound."

vekshin13 years ago
6 0

Answer: Element

Explanation: No, marble is not a compound, because for a rock to be called marble other characteristics, beyond the chemical composition, have to have specific values. But marble is made up of only one compound, calcium carbonate. Colored marbles do contain small amounts of other chemicals.

You might be interested in
If 5. 0 grams of kcl is dissolved in 500 ml of water, what is the concentration of the resulting solution?
Lady_Fox [76]

If 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.

<h3>How to calculate concentration?</h3>

The concentration of a solution can be calculated by using the following formula;

Molarity = no of moles ÷ volume

According to this question, 5.0 grams of KCl is dissolved in 500 ml of water. The concentration is calculated as follows:

no of moles of KCl = 5g ÷ 74.5g/mol = 0.067mol

Molarity = 0.067mol ÷ 0.5L = 0.134M

Therefore, if 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.

Learn more about concentration at: brainly.com/question/10725862

#SPJ1

6 0
2 years ago
Determine the oxidation states of the elements in the compounds listed. None of the oxygen-containing compounds are peroxides or
natka813 [3]

Answer:

Explanation:

You need to remember that the oxidation number of H is +1, except when it is in a metal hydrites like NaH, where its oxidation number is -1. Then, the oxidation number of O is -2, but in peroxides is -1. So with these rules you just have to multiply the ox. number with the name of atoms and all the elements in the reaction must sum 0.

5 0
3 years ago
Which of the following would improve the experimental design of this investigation? why?
Sliva [168]

Answer:

ask your teaacher

Explanation:

3 0
3 years ago
Calculate the specific heat capacity for a 22.7-g sample of lead that absorbs 237 J when its temperature increases from 29.8 °C
soldier1979 [14.2K]

Answer:

\boxed {\boxed {\sf c\approx 0.159 \ J/ g \textdegree C}}

Explanation:

We are asked to find the specific heat capacity of a sample of lead. The formula for calculating the specific heat capacity is:

c= \frac{Q}{m \times \Delta T}

The heat absorbed (Q) is 237 Joules. The mass of the lead sample (m) is 22.7 grams. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature. The temperature increases <em>from</em> 29.8 °C <em>to </em>95.6 °C.

  • ΔT = final temperature -inital temperature
  • ΔT= 95.6 °C - 29.8 °C = 65.8 °C

Now we know all three variables and can substitute them into the formula.

  • Q= 237 J
  • m= 22.7 g
  • ΔT = 65.8 °C

c= \frac {237 \ J}{22.7 \ g  \ \times  \ 65.8 \textdegree C}

Solve the denominator.

  • 22.7 g * 65.8 °C = 1493.66 g °C

c= \frac {237 \  J}{1493.66 \ g \textdegree C}

Divide.

c= 0.1586706479 J /g \textdegree C

The original values of heat, temperature, and mass all have 3 significant figures, so our answer must have the same. For the number we found that is the thousandth place. The 6 in the ten-thousandth place tells us to round the 8 up to a 9.

c \approx 0.159 \ J/g \textdegree C

The specific heat capacity of lead is approximately <u>0.159 Joules per gram degree Celsius.</u>

3 0
3 years ago
a length of #8 copper wire (radius = 1.63 mm) has a mass of 24.0 Kg and a resistance of 2.061 Ohm per Km. What is the over all r
lubasha [3.4K]
V = m / ρ 
<span>V = (23,200/8.96) × 1000 </span>
<span>V = 2,589,285.71 mm³ </span>

<span>Now we have volume and given the radius we can solve for its length. </span>
<span>L = V/πr² </span>
<span>L = (2,589,285.71/(π×1.63²))/1×10^6 </span>
<span>L = 0.31 km </span>

<span>So </span>
<span>R = rL </span>
<span>R = 2.061(0.31) </span>
<span>R = .6389 Ω </span>

<span>End.</span>
6 0
3 years ago
Read 2 more answers
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