Answer:
The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.
Explanation:
![Q=mc\Delta T](https://tex.z-dn.net/?f=Q%3Dmc%5CDelta%20T)
Where:
Q = heat absorbed or heat lost
c = specific heat of substance
m = Mass of the substance
ΔT = change in temperature of the substance
We have mass of copper = m = 25.3 g
Specific heat of copper = c = 0.385 J/g°C
ΔT = 39°C - 22°C = 17°C
Heat absorbed by the copper :
![Q=25.3 g\times 0.385 J/g^oC\times 17^oC=165.59 J](https://tex.z-dn.net/?f=Q%3D25.3%20g%5Ctimes%200.385%20J%2Fg%5EoC%5Ctimes%2017%5EoC%3D165.59%20J)
The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.
Answer:
44 years will take for 10 grams of Actinium to decay until there were only 2.5 grams.
Explanation:
The half life it tell you about the time in which half of the quantity of the isotope will decay.
time (years) quantity of isotope (grams)
0 10
22 5
44 2.5
The 3 and 2 to the right of the components are subscriptions.
Answer:
of liquid sodium is required.
Explanation: To calculate the mass of liquid sodium, we use the formula:
![q=nc\Delta T\\q=\frac{m}{M}c\Delta T](https://tex.z-dn.net/?f=q%3Dnc%5CDelta%20T%5C%5Cq%3D%5Cfrac%7Bm%7D%7BM%7Dc%5CDelta%20T)
where,
q = heat required,
(Conversion factor: 1MJ = 1000000J)
m = Mass of liquid sodium, ![?g](https://tex.z-dn.net/?f=%3Fg)
M = Molar mass of liquid sodium, ![23g/mol](https://tex.z-dn.net/?f=23g%2Fmol)
c = Specific heat capacity, ![30.8J/Kmol](https://tex.z-dn.net/?f=30.8J%2FKmol)
= change in temperature,
(Conversion factor: 0°C = 273K)
Putting values in above equation, we get:
![8.60\times 10^6J=\frac{m}{23g/mol}\times 30.8J/Kmol\times 10K](https://tex.z-dn.net/?f=8.60%5Ctimes%2010%5E6J%3D%5Cfrac%7Bm%7D%7B23g%2Fmol%7D%5Ctimes%2030.8J%2FKmol%5Ctimes%2010K)
![m=64.216\times 10^4grams](https://tex.z-dn.net/?f=m%3D64.216%5Ctimes%2010%5E4grams)
Answer:
Explanation:
a )
energy produced per second = 500 J
Heat produced = 500 x .8 = 400 J per second.
If m be the mass of water evaporated per unit hour
m x latent heat = 400 x 60 x 60
= m x 2.42 x 10⁶ = 1.44 x 10⁶
m = .595 kg per hour
b )
volume of water = 595 mL
bottles = 595 / 750
.8 or 4/5 of bottle. per hour.