Answer:
B) Iron(lll) phosphate, FePO4
V1/T1=V2/T2
(15.5)/(360K)=(3.6)/(T2)
T2=83.61290K
T2=-189.3871 degrees Celsius
<h3>
Answer:</h3>
D. CH₃O₆
<h3>
Explanation:</h3>
- We are given the ratio of carbon, hydrogen and oxygen in a compound as 14: 42 : 84
We are supposed to determine the empirical formula of the compound;
- We need to know what is an empirical formula;
- An empirical formula of a compound is a formula that shows the simplest whole number ratio of elements in a compound.
In this case;
The ratio of C : H : O is 14 : 42 : 84
- Note, this is not the simplest ratio.
But we can simplify further to get the simplest whole number ratio;
- Therefore, 14 : 42 : 84 is equal to 1 : 3 : 6
- Thus, the simplest whole number ratio of C : H : O in the compound is 1 : 3 : 6
- Therefore, the empirical formula of the compound is CH₃O₆
Answer:
V = 25.7 L
Explanation:
To find the volume of Argon (Ar), you need to use the Ideal Gas Law equation. This looks like:
PV = nRT
In this formula,
> P = pressure (atm)
> V = volume (L)
> n = number of moles
> R = constant (0.0821 L*atm/K*mol)
> T = temperature (K)
While there is a different constant that can be used if you want to keep the pressure in mmHg, there is a more common constant used when the pressure is in atm. So, to find the volume, you need to (1) convert mmHg to atm (by dividing by 760) and then (2) calculate the volume (using Ideal Gas Law).
<u>(Step 1)</u>
600 mm Hg 1 atm
------------------- x --------------------- = 0.789 atm
760 mm Hg
<u>(Step 2)</u>
PV = nRT
(0.789 atm) x V = (0.825 mole)(0.0821 L*atm/K*mol)(300 K)
(0.789 atm) x V = 20.32
V = 25.7 L
