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Kazeer [188]
2 years ago
14

When starting a foot race, a 64 kilogram sprinter exerts an average force of 693 newtons backward on the ground for 0.59 seconds

. how far does he travel in meters during this time?
Physics
1 answer:
cluponka [151]2 years ago
6 0

The distance traveled by the sprinter in meters is determined as 1.88 m.

<h3>Acceleration of the sprinter</h3>

The acceleration of the sprinter is the rate of change of velocity of the sprinter with time.

The acceleration of the sprinter is calculated as follows;

Apply Newton's second law of motion as follows;

F = ma

a = F/m

where;

  • F is the applied force by the sprinter
  • m is mass of the sprinter
  • a is acceleration of the sprinter

a = 693 N / 64 kg

a = 10.83 m/s²

<h3>Distance traveled by the sprinter</h3>

The distance traveled by the sprinter is calculated as follows;

s = ut + ¹/₂at²

where;

  • u is initial velocity = 0

s = ¹/₂at²

where;

  • t is time of motion
  • a is acceleration

s = (0.5)(10.83)(0.59²)

s = 1.88 m

Thus, the distance traveled by the sprinter in meters is determined as 1.88 m.

Learn more about distance here: brainly.com/question/2854969

#SPJ1

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Irina18 [472]

Answer:

T_ww = 43,23°C

Explanation:

To solve this question, we use energy balance and we state that the energy that enters the systems equals the energy that leaves the system plus losses. Mathematically, we will have that:

E_in=E_out+E_loss

The energy associated to a current of fluid can be defined as:

E=m*C_p*T_f

So, applying the energy balance to the system described:

m_CW*C_p*T_CW+m_HW*C_p*T_HW=m_WW*C_p*T_WW+E_loss

Replacing the values given on the statement, we have:

1.0 kg/s*4,18 kJ/(kg°C)*25°C+0.8  kg/s*4,18 kJ/(kg°C)*75°C=1.8 kg/s*4,18 kJ/(kg°C)*T_WW+30  kJ/s

Solving for the temperature Tww, we have:

(1.0 kg/s*4,18 kJ/(kg°C)*25°C+0.8 kg/s*4,18 kJ/(kg°C)*75°C-30 kJ/s)/(1.8 kg/s*4,18 kJ/(kg°C))=T_WW

T_WW=43,23 °C

Have a nice day! :D

6 0
3 years ago
Describe an experiment to show that pressure increases with the decrease in the area of surface
cluponka [151]
Answer:
press a baloon against one pin it bursts
but now arrange lot of pins parallel closely to each other if u press a baloon against them it does not burst hope this helps u
7 0
3 years ago
Nellie pulls on a 10kg wagon with a constant horizontal force of 30N. If there are no other horizontal forces, what is the wagon
s2008m [1.1K]

Answer:

The acceleration of the wagon is 3 m/s².

To calculate the acceleration of the wagon, we use the formula below.

Formula:

F = ma............. Equation 1

Where:

F = horizontal Force

m = mass of the wagon

a = acceleration of the wagon.

make a the subject of the equation

a = F/m.............. Equation 2

From the question,

Given:

F = 30 N

m = 10 kg

Substitute these values into equation 2

a = 30/10

a = 3 m/s²

Hence, the acceleration of the wagon is 3 m/s².

5 0
2 years ago
What is the minimum tangential velocity a space station would need to simulate earth gravity if the radius is 50 meters ?
Aneli [31]

Explanation:

angular velocity is given by

w =  \sqrt{ \frac{g}{r} }

w =  \sqrt{ \frac{9.8}{25} }

w = 0.626

now tangential velocity is

V = rw

= 25 x 0.626

= 15.65 m/s

5 0
3 years ago
A 477 g portion of soup is heated in a microwave oven from 25°C to 90°C, using radiation with a wavelength of 1.55 × 10⁻² m. Ass
zheka24 [161]

To solve this problem we will use the heat transfer equations, to determine the amount of heat added to the body. Subsequently, through the energy ratio given by Plank, we will calculate the energy of each of the photons. The relationship between total energy and unit energy will allow us to determine the number of photons

The mass of water in the soup is 477g

The change in temperate is

\Delta T = (90+273K)-(25+273K) = 65K

Use the following equation to calculate the heat required to raise the temperature:

q = mc\Delta T

Here,

m = Mass

c = Specific Heat

q = (477)(4.184)(65)

q = 129724.92J

The wavelength of the ration used for heating is 1.55*10^{-2}m

The number of photons required is the rate between the total energy and the energy of each proton, then

\text{Number of photons} = \frac{\text{Total Energy}}{\text{Energy of one Photon}}

This energy of the photon is given by the Planck's equation which say:

E = \frac{hc}{\lambda}

Here,

h = Plank's Constant

c = Velocity of light

\lambda = Wavelength

Replacing,

E = \frac{(6.626*10^{-34})(3*10^8)}{1.55*10^{-2}}

E = 1.28*10^{-23}J

Now replacing we have,

\text{Number of photons} = \frac{82240.7}{1.28*10^{-23}}

\text{Number of photons} = 6.41*10^{27}

Therefore the number of photons required for heating is 6.41*10^{27}

4 0
3 years ago
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