Explanation:
It is given that,
Mass of an electron,
Initial speed of the electron,
Final speed of the electron,
Distance, d = 5 cm = 0.05 m
(a) The acceleration of the electron is calculated using the third equation of motion as :
Force exerted on the electron is given by :
(b) Let W is the weight of the electron. It can be calculated as :
Comparison,
Hence, this is the required solution.
The power is 833.3 W
Explanation:
First of all, we need to calculate the work done in lifting the barbell, which is equal to the change in gravitational potential energy of the barbell:
where
mg = 1250 N is the weight of the barbell
h = 2 m is the change in height
Substituting,
Now we can calculate the power, which is equal to the work done per unit time:
where
W = 2500 J is the work done
t = 3 s is the time taken
Substituting,
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