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gregori [183]
3 years ago
15

According to the principle of conservation of momentum, A. the amount of momentum of all the objects in the universe is constant

. B. in an open system, the total amount of momentum of the objects is conserved. C. in a closed system, the speed of any two colliding objects will remain constant. D. in a closed system, an object's momentum before a collision will equal its momentum after the collision.
Physics
1 answer:
anygoal [31]3 years ago
6 0

Answer:

D. in a closed system, an object's momentum before a collision will equal its momentum after the collision.

Explanation:

As we know by newton's II law we have

F = \frac{\Delta P}{\Delta t}

so we will have

F = net force on the system

\Delta P = change in momentum

so we can say if the momentum is conserved or the initial momentum of the system will be equal to the final momentum of the system

then we will say that

\Delta P = 0

so net force on the system must be ZERO

so in such type of questions the system must be isolated and there is no external force on it

so correct answer will be

D. in a closed system, an object's momentum before a collision will equal its momentum after the collision.

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A 9.00 g bullet is fired horizontally into a 1.20 kg wooden block resting on a horizontal surface. The coefficient of kinetic fr
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Answer:

The initial speed of bullet is "164 m/s".

Explanation:

The given values are:

mass of bullet,

m'=9.00 \ g

or,

    =0.009 \ kg

mass of wooden block,

m=1.20 \ kg

speed,

s=0.390 \ m

Coefficient of kinetic friction,

\mu=0.20

As we know,

The Kinematic equation is:

⇒  v^2=u^2+2as

then,

Initial velocity will be:

⇒  u=v^2-2as

        =v^2-2 \mu gs

On substituting the given values, we get

⇒  u=\sqrt{0-2\times 0.20\times 9.8\times 0.390}

       =\sqrt{-1.5288}

       =1.23 \ m/s

As we know,

The conservation of momentum is:

⇒  mu=m'u'

or,

⇒ Initial speed, u'=\frac{mu}{m'}

On substituting the values, we get

⇒                            =\frac{1.20\times 1.23}{0.009}

⇒                            =\frac{1.476}{0.009}

⇒                            =164 \ m/s                              

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