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gregori [183]
3 years ago
15

According to the principle of conservation of momentum, A. the amount of momentum of all the objects in the universe is constant

. B. in an open system, the total amount of momentum of the objects is conserved. C. in a closed system, the speed of any two colliding objects will remain constant. D. in a closed system, an object's momentum before a collision will equal its momentum after the collision.
Physics
1 answer:
anygoal [31]3 years ago
6 0

Answer:

D. in a closed system, an object's momentum before a collision will equal its momentum after the collision.

Explanation:

As we know by newton's II law we have

F = \frac{\Delta P}{\Delta t}

so we will have

F = net force on the system

\Delta P = change in momentum

so we can say if the momentum is conserved or the initial momentum of the system will be equal to the final momentum of the system

then we will say that

\Delta P = 0

so net force on the system must be ZERO

so in such type of questions the system must be isolated and there is no external force on it

so correct answer will be

D. in a closed system, an object's momentum before a collision will equal its momentum after the collision.

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Two horizontal forces act on a 1.4 kg chopping block that can slide over a friction-less kitchen counter, which lies in an xy pl
kogti [31]

Answer:

Part a)

a = (0.64\hat i - 0.5 \hat j)m/s^2

Part b)

a = (0.64\hat i + 5.21 \hat j)m/s^2

Part c)

a = (4.92\hat i - 0.5 \hat j)m/s^2

Explanation:

As per Newton's II law we know that

F = ma

so we will have

a = \frac{F}{m}

so we will have

a = \frac{F_1 + F_2}{m}

Part a)

a = \frac{(3.9 \hat i + 3.3 \hat j) + (-3\hat i - 4\hat j)}{1.4}

a = \frac{0.9 \hat i - 0.7 \hat j}{1.4}

a = (0.64\hat i - 0.5 \hat j)m/s^2

Part b)

a = \frac{(3.9 \hat i + 3.3 \hat j) + (-3\hat i + 4\hat j)}{1.4}

a = \frac{0.9 \hat i + 7.3 \hat j}{1.4}

a = (0.64\hat i + 5.21 \hat j)m/s^2

Part c)

a = \frac{(3.9 \hat i + 3.3 \hat j) + (3\hat i - 4\hat j)}{1.4}

a = \frac{6.9 \hat i - 0.7 \hat j}{1.4}

a = (4.92\hat i - 0.5 \hat j)m/s^2

3 0
3 years ago
A ball is thrown horizontally at a speed of 16 m/s from the top of a cliff. If the ball hits the ground 6.0 s later, approximate
lina2011 [118]

Answer:

Y = 176.4 m

Explanation:

For the height of cliff we will analyze the vertical motion. We will apply the 2nd equation of motion:

Y = V₀y*t + (0.5)gt²

where,

Y = Height = ?

V₀y = Initial Vertical Velocity = 0 m/s (since, ball is thrown horizontally)

t = time = 6 s

g = 9.8 m/s²

Therefore,

Y = (0 m/s)(6 s) + (0.5)(9.8 m/s²)(6 s)²

<u>Y = 176.4 m</u>

3 0
3 years ago
Which of the following is the name of the process scientists use to gain
harkovskaia [24]

Answer:

b

Explanation:

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6 0
3 years ago
An ideal monatomic gas initially has a temperature of 300 K and a pressure of 5.79 atm. It is to expand from volume 420 cm3 to v
maxonik [38]

Answer:

a) The final pressure is 1.68 atm.

b) The work done by the gas is 305.3 J.

Explanation:

a) The final pressure of an isothermal expansion is given by:

T = \frac{PV}{nR}

T_{i} = T_{f}

\frac{P_{i}V_{i}}{nR} = \frac{P_{f}V_{f}}{nR}

Where:

P_{i}: is the initial pressure = 5.79 atm

P_{f}: is the final pressure =?

V_{i}: is the initial volume = 420 cm³

V_{f}: is the final volume = 1450 cm³

n: is the number of moles of the gas

R: is the gas constant

P_{f} = \frac{P_{i}V_{i}}{V_{f}} = \frac{5.79 atm*420 cm^{3}}{1450 cm^{3}} = 1.68 atm

Hence, the final pressure is 1.68 atm.

b) The work done by the isothermal expansion is:

W = P_{i}V_{i}ln(\frac{V_{f}}{V_{i}}) = 5.79 atm*\frac{101325 Pa}{1 atm}*420 cm^{3}*\frac{1 m^{3}}{(100 cm)^{3}}ln(\frac{1450 cm^{3}}{420 cm^{3}}) = 305.3 J

Therefore, the work done by the gas is 305.3 J.

I hope it helps you!        

3 0
3 years ago
Select True or False for the following statements about conductors in electrostatic equilibrium. All points of a conductor are a
erik [133]

Answers :

1. All points of a conductor are at the same potential. - True

2. Charges prefer to be uniformly distributed throughout the volume of a conductor. - False

3 The electric field inside the conducting material is always zero. -True

4.Just outside the surface of a conductor, the electric field is always zero. - False

4 0
3 years ago
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