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4 years ago

Light enters a substance from air at 30 degrees to thenormal.

Physics

1 answer:

Gwar [14]4 years ago

5 0

Answer:

Explanation:

The angle of incidence and refraction are both measured from the normal

angle of incidence = 30°

angle of refraction = 23°

refractive index(n) = sini / sinr

n = sin30°/sin23°

n = 1.27965

refractive index (n) = 1/sinC

where C is the critical angle.

sinC= 1/n

C =arcsin (1/n)

C =arcsin (1/1.27965)

C = 51.39°

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A satellite of mass 5460 kg orbits the Earth and has a period of 6520 s

Nikolay [14]

Answer:

what if I do and b then someone else c I don't have enough time pls

8 0

3 years ago

Find the shear stress and the thickness of the boundary layer (a) at the center and (b) at the trailing edge of a smooth flat pl

melomori [17]

Answer:

a) The shear stress is 0.012

b) The shear stress is 0.0082

c) The total friction drag is 0.329 lbf

Explanation:

Given by the problem:

Length y plate = 2 ft

Width y plate = 10 ft

p = density = 1.938 slug/ft³

v = kinematic viscosity = 1.217x10⁻⁵ft²/s

Absolute viscosity = 2.359x10⁻⁵lbfs/ft²

a) The Reynold number is equal to:

$Re=\frac{1*3}{1.217x10^{-5} } =246507, laminar$

The boundary layer thickness is equal to:

$\delta=\frac{4.91*1}{Re^{0.5} } =\frac{4.91*1}{246507^{0.5} } =0.0098$ ft

The shear stress is equal to:

$\tau=0.332(\frac{2.359x10^{-5}*3 }{1} )(246507)^{0.5} =0.012$

b) If the railing edge is 2 ft, the Reynold number is:

$Re=\frac{2*3}{1.215x10^{-5} } =493015.6,laminar$

The boundary layer is equal to:

$\delta=\frac{4.91*2}{493015.6^{0.5} } =0.000019ft$

The sear stress is equal to:

$\tau=0.332(\frac{2.359x10^{-5}*3 }{2} )(493015.6^{0.5} )=0.0082$

c) The drag coefficient is equal to:

$C=\frac{1.328}{\sqrt{Re} } =\frac{1.328}{\sqrt{493015.6} } ==0.0019$

The friction drag is equal to:

$F=Cp\frac{v^{2} }{2} wL=0.0019*1.938*(\frac{3^{2} }{2} )(10*2)=0.329lbf$

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3 years ago

Which of the following factors affects the pressure of an enclosed gas

PIT_PIT [208]

The answer is:

All the above

The explanation:

The volume and the temperature and the number of particles will affect the pressure of an enclosed gas.

because according to boyle's law when the temperature constant so the pressure and volume of a gas have an inverse relationship, when temperature is constant.

when:

PV = nRT

when p is the pressure

V is the volume

n is number of moles

T is temperature

from this law we can know that there is a relation between P and V and when n has a relation with the number of particles so:

volume , temperature and number of particles affect the pressure of an enclosed gas.

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3 years ago

You push against a steamer trunk with a force of 750 N at an angle of 25° with the horizontal . The trunk is on a flat floor and

djverab [1.8K]

This means that the horizontal force is 750sin(25°). To be able to move the truck, force applied must be greater than static friction, which equals to its coefficient (0.77) x normal contact force (= weight)

Hence, 750sin(25°) = 0.77mg. m = 750sin(25°)/(0.77g)

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3 years ago

Leta stetter hollingworth conducted pioneering work on __________. a. identity development in ethnic minorities b. cognitive pro

Elena L [17]

D. Leta stetter hollingworth conducted pioneering work on <u>adolescent development and gifted children</u>.

<h3>Who is Leta stetter hollingworth?</h3>

Leta stetter hollingworth is an early feminist and active member of the Women's Suffrage Party.

Leta Stetter Hollingworth is best known for her landmark contributions to the psychology of women and to education of the gifted. That is adolescent development and gifted children.

Thus, we can conclude that Leta stetter hollingworth conducted pioneering work on <u>adolescent development and gifted children</u>.

Learn more about Leta stetter hollingworth here: brainly.com/question/2680369

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1 year ago