Answer: B
Step-by-step explanation:
Answer:
h²⁴
Step-by-step explanation:
Emm... Do you mean (frac(h¹²)/(h⁴))³? If so, here is a solition: h¹²/h⁴=h⁸ and 8×3=24, so answer is h²⁴. Please use formula editor next time) Have a nice day))
5/6 is not the definite ratio, when you take a larger sample size it could be off by a bit like 499/600 or 501/600
18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.
<u>Step-by-step explanation:</u>
Let x = kg of 15% copper alloy
Let y = kg of 60% copper alloy
Since we need to create 90 kg of alloy we know:
x + y = 90
51% of 90 kg = 45.9 kg of copper
So we're interested in creating 45.9 kg of copper
We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:
0.15x + 0.60y = 45.9
but
x + y = 90
x= 90 - y
substituting that value in for x
0.15(90 - y) + 0.60y = 45.9
13.5 - 0.15y + 0.60y = 45.9
0.45y = 32.4
y = 72
Substituting this y value to solve for x gives:
x + y = 90
x= 90-72
x=18
Therefore, in order to create 90kg of 51% alloy, we'd need 18 kg of 15% copper and 72 kg of 60% copper.
Answer:
Equation:(4 2/5)/2/5=? ; estimate: a
little more than 10 magazines; answer:
11 magazines in the stack.
Step-by-step explanation:
