Question

Answer part ABCDE B options is Z , T , chi-square, F

Answer 1

1. The null and alternative hypotheses would be given by H₀: μ = 7 and H₀: μ ≠ 7.
2. The test statistic is equal to 1.198.
3. The p-value is equal to 0.1262.
4. In conclusion, yes the mean discharge differs from 7 fluid ounces.

What is a null hypothesis?

A null hypothesis (H₀) can be defined the opposite of an alternate hypothesis (H₁) and it asserts that two (2) possibilities are the same.

How to calculate value of the test statistic?

The test statistic can be calculated by using this formula:

$t=\frac{x\;-\;u}{\frac{\delta}{\sqrt{n} } }$

Where:

• x is the sample mean.

• u is the mean.

• is the standard deviation.

• n is the number of hours.

For this clinical trial (study), we should use a t-test and the null and alternative hypotheses would be given by:

H₀: μ = 7

H₀: μ ≠ 7

Next, we would calculate the t-test as follows:

$t=\frac{7.08\;-\;7}{\frac{0.25}{\sqrt{14} } }\\\\t=\frac{0.08}{\frac{0.25}{3.7417 } }$

t = 0.08/0.0668

t = 1.198.

For the p-value, we have:

P-value = P(t < 1.198)

P-value = 0.1262.

Therefore, the p-value (0.1262) is greater than α = 0.10. Based on this, we should fail to reject the null hypothesis.

In conclusion, yes the mean discharge differs from 7 fluid ounces.

Read more on null hypothesis here: brainly.com/question/14913351

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