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mezya [45]
2 years ago
12

A rectangular container of air measures 1.2 x 10-2 m by 8.34 x 10 1 m by 6.0 x 10-1 m. Air

Chemistry
1 answer:
Dominik [7]2 years ago
8 0

The volume of the rectangle has been given by the product of length, breadth, and height. The mass of the air with a density of 1180 g/m³ is 708.57 gms.

<h3>What is density?</h3>

The density of the substance has been known to be given by the mass's ratio to the volume. The formula for density is given as,

Density = Mass ÷ Volume

Given,

Density = 1180 g/m³

The volume of the rectangle = L×B×H

Substituting the values above,

Mass = Density × Volume

M = 1180 × 1.2 × 10⁻² × 8.34 × 10¹ × 6.0 × 10⁻¹

= 708.57 gm

Therefore, the mass of the air is 708.57 gms.

Learn more about density here:

brainly.com/question/952755

#SPJ1

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kipiarov [429]

Answer:

its true i just looked on quizlet

Explanation:

8 0
2 years ago
What is an aqueous solution? What is an aqueous solution? An aqueous solution is a homogeneous mixture of a substance with water
mestny [16]

Answer:

The answer to your question is: first option.

Explanation:

What is an aqueous solution?

Aqueous solution is a solution which solvent is water and is homogeneous.

a) An aqueous solution is a homogeneous mixture of a substance with water.  This is the correct definition of aqueous solution because it mentions the characteristics of this kind of solutions.

b) An aqueous solution is a dispersoid solution. This option is wrong, it is a homogeneous solution, and the description do not mention water.

c) An aqueous solution is a mixture of a liquid substances. Aqueous solution is a mixture but one of the components is water not a liquid substance.

d) An aqueous solution is a heterogeneous mixture of a substance with water. Aqueous solution is homogeneous not heterogeneous, this option is wrong.

5 0
3 years ago
Calculate the specific heat capacity for a 15.3-g sample of gold that absorbs 87.2 J when its temperature increases from 35.0 °C
diamong [38]

Answer:

The specific heat of gold is 0.129 J/g°C

Explanation:

Step 1: Data given

Mass of gold  = 15.3 grams

Heat absorbed = 87.2 J

Initial temperature = 35.0 °C

Final temperature = 79.2 °C

Step 2:

Q = m*c*ΔT

⇒ Q =the heat absorbed = 87.2 J

⇒ m = the mass of gold = 15.3 grams

⇒ c = the specific heat of gold = TO BE DETERMINED

⇒ ΔT = The change in temperature = T2 - T1 = 79.2 - 35.0 = 44.2 °C

87.2 J = 15.3g * c * 44.2°C

c = 87.2 / (15.3 * 44.2)

c = 0.129 J/g°C

The specific heat of gold is 0.129 J/g°C

4 0
3 years ago
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igor_vitrenko [27]
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5. A sample of methane has a volume of 225 mL at 0.650 atm of pressure. What will the new volume be if the
Norma-Jean [14]

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not sure

Explanation:

8 0
2 years ago
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