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Artist 52 [7]
3 years ago
12

Which of the three gases will have the highest average kinetic energy at a given temperature

Chemistry
1 answer:
Alona [7]3 years ago
4 0

This is an incomplete question, here is a complete question.

Which of the three gases will have the highest average kinetic energy at a given temperature?

A) HBr

B) NO₂

C) C₂H₆

Answer : All three gases will have the same average kinetic energy at a given temperature.

Explanation :

The formula for average kinetic energy is:

K.E=\frac{3}{2}kT

where,

K.E = average kinetic energy

k = Boltzmann’s constant

T = temperature

As we know that, average kinetic energy depends only on the temperature.

As the temperature of the all three gases are same. So, the all three gases will have the same average kinetic energy.

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what is the correct conversion factor by which to multiply to convert moles of nitrogen to moles of ammonium nitrate (NH4NO3)
Ostrovityanka [42]

Answer:

0.5

Explanation:

1 mole of ammonium nitrate contains 2 moles of nirogen

1 mole of nitrogen converts to 0.5  moles of ammonium nitrate

the conversation factor is 0.5

6 0
3 years ago
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What is the charge of oxygen in Na2O?
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In Na2O, what is the oxidation state of oxygen? In Na2O oxidation state of Na is 1+
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2 years ago
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Suppose a 250. mL flask is filled with 0.30 mol of N_2 and 0.70 mol of NO. The following reaction becomes possible:N_2(g) +O2 →
Inessa [10]

Answer:

0.4 M

Explanation:

Equilibrium occurs when the velocity of the formation of the products is equal to the velocity of the formation of the reactants. It can be described by the equilibrium constant, which is the multiplication of the concentration of the products elevated by their coefficients divided by the multiplication of the concentration of the reactants elevated by their coefficients. So, let's do an equilibrium chart for the reaction.

Because there's no O₂ in the beginning, the NO will decompose:

N₂(g) + O₂(g) ⇄ 2NO(g)

0.30 0 0.70 Initial

+x +x -2x Reacts (the stoichiometry is 1:1:2)

0.30+x x 0.70-2x Equilibrium

The equilibrium concentrations are the number of moles divided by the volume (0.250 L):

[N₂] = (0.30 + x)/0.250

[O₂] = x/0.25

[NO] = (0.70 - 2x)/0.250

K = [NO]²/([N₂]*[O₂])

K = \frac{(\frac{0.70 -2x}{0.250})^2 }{\frac{0.30+x}{0.250}*\frac{x}{0.250} }

7.70 = (0.70-2x)²/[(0.30+x)*x]

7.70 = (0.49 - 2.80x + 4x²)/(0.30x + x²)

4x² - 2.80x + 0.49 = 2.31x + 7.70x²

3.7x² + 5.11x - 0.49 = 0

Solving in a graphical calculator (or by Bhaskara's equation), x>0 and x<0.70

x = 0.09 mol

Thus,

[O₂] = 0.09/0.250 = 0.36 M ≅ 0.4 M

3 0
3 years ago
Based on your solubility rules which of the following compounds would form a precipitate water?
Novosadov [1.4K]
H2SO4+NaOH=Na2SO4+H2O
3 0
3 years ago
What is the answer to...
adoni [48]

Answer: short answer short 0.65 / 5.37

15% NaOH by mass is 15g of NaOH in (100-15)g of solution.

No. Of moles of NaOH in solution = 0.65

No of moles of Water in solution = 4.72

Mole Fraction =  

(

(Moles of Solvent)

(Moles Of Solute)+(Moles of Solvent)

)

OR

(

(Moles of Solvent)

Total Number Of Moles

)

= 0.65 / 5.37

= 0.121

Explanation:

Hope this helped

8 0
3 years ago
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