Your answer should be c I think
Answer:
The test solution is acidified using a few drops of dilute nitric acid, and then a few drops of silver nitrate solution are added. Different coloured silver halide precipitates form, depending on the halide ions present: ... iodide ions give a yellow precipitate of silver iodide.
Answer:
Conduction, Convection and Radiation
Explanation:
Answer:
31.9178 °C is the final temperature of the water
Explanation:
![2C_6H_6(l)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)+6542 kJ](https://tex.z-dn.net/?f=2C_6H_6%28l%29%2B15O_2%28g%29%5Crightarrow%2012CO_2%28g%29%2B6H_2O%28l%29%2B6542%20kJ)
Mass of benzene burned = 6.200 g
Moles of benzene burned = ![\frac{6.200 g}{78 g/mol}=0.0794 mol](https://tex.z-dn.net/?f=%5Cfrac%7B6.200%20g%7D%7B78%20g%2Fmol%7D%3D0.0794%20mol)
According to reaction , 2 moles of benzene gives 6542 kJ of energy on combustion.
Then 0.0794 mol of benzene on combustion will give:
![\frac{6542 kJ}{2}\times 0.0794 kJ=259.7174 kJ=Q](https://tex.z-dn.net/?f=%5Cfrac%7B6542%20kJ%7D%7B2%7D%5Ctimes%200.0794%20kJ%3D259.7174%20kJ%3DQ)
Mass of water in which Q heat is added = m = 5691 g
Initial temperature = ![T_i=21^oC](https://tex.z-dn.net/?f=T_i%3D21%5EoC)
Final temperature = ![T_f](https://tex.z-dn.net/?f=T_f)
Specific heat of water = c = 4.18 J/g°C
Change in temperature of water = ![T_f-T_i](https://tex.z-dn.net/?f=T_f-T_i)
![Q=mc\Delta t=mc(T_f-T_i)](https://tex.z-dn.net/?f=Q%3Dmc%5CDelta%20t%3Dmc%28T_f-T_i%29)
![259,717.4 J=5691 g\times 4.18 J/g^oC\times (T_f-21^oC)](https://tex.z-dn.net/?f=259%2C717.4%20J%3D5691%20g%5Ctimes%204.18%20J%2Fg%5EoC%5Ctimes%20%28T_f-21%5EoC%29)
![T_f=31.91 ^oC](https://tex.z-dn.net/?f=T_f%3D31.91%20%5EoC)
31.9178 °C is the final temperature of the water