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trasher [3.6K]
2 years ago
14

What is the molar mass of barium hydroxide

Chemistry
1 answer:
maksim [4K]2 years ago
4 0

Answer:

171.34 g/mol

Explanation:

Ba molar mass = 137.328 g/mol

O molar mass = 15.999 g/mol * 2 = 31.9980 g/mol

H molar mass = 1.008 g/mol * 2 = 2.0160 g/mol

137.328 + 31.9980 + 2.0160 = 171.3420 = 171.34 g/mol

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The particles in a solid are tightly packed and locked in place. ... The particles in a liquid are close together (touching) but they are able to move/slide/flow past each other. The particles in a gas are fast moving and are able to spread apart from each other.

Explanation:

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Ted used a balance scale to weigh a 2.233 g sample of copper sulfate. Which of these measurements made by Ted is the most accura
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If I touch a hot object, my hand gets hot through which type of heat transfer?
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Given the two half-cell reactions for copper and iron below
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3 years ago
The true absorbance for a 1.0 x 10 −5 M solution is 0.7526. If the percentage stray light for a spectrophotometer is 0.56%, calc
Korvikt [17]

Answer:

The percentage deviation is  \Delta M = 1.87%

Explanation:

From the question we are told that  

     The concentration is of the solution is C = 1.0*10^{-5} M

     The true absorbance A = 0.7526

      The percentage of transmittance due to stray light z = 0.56% =\frac{0.56}{100}  = 0.0056

Generally Absorbance is mathematically represented as

           A = -log T

Where T is  the percentage of true transmittance

    Substituting value  

          0.7526 = - log T

              T = 10^{-0.7526}

                  = 0.177

                  = 17.7%

The Apparent absorbance is mathematically represented

           A_p = -log (T +z)

Substituting values

           A_p = -log(0.177 + 0.0056)

                = -log(0.1826)

               = 0.7385

The percentage by which apparent absorbance deviates from known absorbance is mathematically evaluated as

       \Delta A = \frac{A -A_p}{A} * \frac{100}{1}

              = \frac{0.7526 - 0.7385}{0.7526} * \frac{100}{1}

             \Delta A = 1.87%  

Since Absorbance varies directly with concentration the percentage deviation of the apparent concentration from know concentration  is

              \Delta M = 1.87%

           

6 0
3 years ago
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