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3 years ago

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Rubbing alcohol is 70.% (m/v) isopropyl alcohol by volume. how many ml of isopropyl alcohol are in a 1 pint (473 ml) container?

2 answers:

g100num [7]3 years ago

8 0

The number of ml of isopropyl alcohol that are 1 pint (473 Ml) is 331.1 Ml

calculation

assume that the 1 pint is in a container

This implies that the 1 pint (473 ml) is in 100 % M/V
what about 70 %(M/V)

that is 473 Ml = 100 %
? = 70 %

by cross multiplication
= 473 x70/100 = 331.1 Ml

Volgvan3 years ago

7 0

Hello!

Rubbing alcohol is 70.% (m/v) isopropyl alcohol by volume. how many ml of isopropyl alcohol are in a 1 pint (473 ml) container?

We have the following information:

% V/V (percentage of volume per volume) = 70

V1 (solute volume) = ? (in mL)

V (volume of the solution) = 473 mL

We apply the data to the formula of volume percentage of the solute per volume of solution, we will have:

$\%\:v/v = \dfrac{v_1}{v} *100$

$70 = \dfrac{v_1}{473}*100$

$70*473 = 100*v_1$

$33110 = 100\:v_1$

$100\:v_1 = 33110$

$v_1 = \dfrac{3311\diagup\!\!\!\!0}{10\diagup\!\!\!\!0}$

$\boxed{\boxed{v_1 = 331.1\:mL\:of\:isopropyl\:alcohol}}\Longleftarrow(solute\:volume)\:\:\:\:\:\:\bf\purple{\checkmark}$

Answer:

331.1 ml of isopropyl alcohol

________________________

$\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}$

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The question is incomplete, complete question is;

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