Question

Rubbing alcohol is 70.% (m/v) isopropyl alcohol by volume. how many ml of isopropyl alcohol are in a 1 pint (473 ml) container?

Answer 1

 The number  of ml of isopropyl  alcohol  that are 1 pint (473 Ml)   is  331.1 Ml

   calculation
 
assume  that  the 1 pint  is in  a  container

   This implies  that the 1 pint (473 ml)  is  in 100 %  M/V
      what about 70 %(M/V)

 that is  473 Ml  = 100 %
                   ?   =   70 %

by  cross  multiplication
    =  473 x70/100 = 331.1 Ml

Answer 2

Hello!

Rubbing alcohol is 70.% (m/v) isopropyl alcohol by volume. how many ml of isopropyl alcohol are in a 1 pint (473 ml) container?

We have the following information:  

% V/V (percentage of volume per volume) = 70  

V1 (solute volume) = ? (in mL)  

V (volume of the solution) = 473 mL

We apply the data to the formula of volume percentage of the solute per volume of solution, we will have:  

$\%\:v/v = \dfrac{v_1}{v} *100$

$70 = \dfrac{v_1}{473}*100$

$70*473 = 100*v_1$

$33110 = 100\:v_1$

$100\:v_1 = 33110$

$v_1 = \dfrac{3311\diagup\!\!\!\!0}{10\diagup\!\!\!\!0}$

$\boxed{\boxed{v_1 = 331.1\:mL\:of\:isopropyl\:alcohol}}\Longleftarrow(solute\:volume)\:\:\:\:\:\:\bf\purple{\checkmark}$

Answer:

331.1 ml of isopropyl alcohol

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