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1 year ago

Five pounds is equal to 2.268 kilograms. How many kilograms is 2 pounds?

Mathematics

1 answer:

Rudik [331]1 year ago

4 0

<h2>Mass conversion</h2>

<em>Mass is the amount of matter that a body possesses and its unit in the </em><em>international system</em><em> of units is the</em><em> kilogram.</em>

<h3>How many kilograms is 2 pounds?</h3>

<em>Knowing that </em><em>1 pound is 2.205 kilograms.</em>

<h3><em>Therefore ⇒ 2 lb * 1 kg / 2.205 lb = 0.907 kg</em></h3>

<em />

Answer: In 2 pounds there are 0.907 kilograms.

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Variation table of this <br> g(x)=2x^3 -x^2 -4x +6

Mrac [35]

Answer:

$2x^{3} - x^{2} - 4x +6$

2x-x-4 $x^{3-2}$ + 6

-3x+6

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2 years ago

Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z

Oliga [24]

Given the expression

$54m^3n\:+\:81m^4n^2$

Apply exponent rule: $a^{b+c}=a^ba^c$

$54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn$ ∵ $m^4n^2=m^3mnn$

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

$=2\cdot \:27m^3n+3\cdot \:27m^3mnn$

Factor out the common term: 27m³n

$=27m^3n\left(2+3mn\right)$

Therefore,

$54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)$

Given the expression

$15x^2y^3z+25x^3y^2z+35x^2y^2z$

Apply exponent rule: $a^{b+c}=a^ba^c$

$15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z$

Rewrite as

$=3\cdot \:5y^2x^2zy+5\cdot \:5y^2x^2zx+7\cdot \:5y^2x^2z$

Factor out common term 5y²x²z

$=5y^2x^2z\left(3y+5x+7\right)$

Therefore,

$15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)$

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2 years ago

The value of a new car in 2015 was 40,000 dollar. It depreciates each year by 7%. How much will the car be worth in 2026?

tiny-mole [99]

Answer:

9200 dollars

Step-by-step explanation:

just minus it 77%

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2 years ago

Why is 4,536 less than 4,563

kkurt [141]

Well, one number is larger than the other, it has a bigger quantity, which makes the other smaller.

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2 years ago

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The National Assessment of Educational Progress (NAEP) includes a mathematics test for eighth-graders. Scores on the test range

LiRa [457]

Answer:

Its standard deviation is 3.79.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\sigma = 125, n = 1089$

$s = \frac{125}{\sqrt{1089}} = 3.79$

Its standard deviation is 3.79.

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3 years ago