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AlladinOne [14]
3 years ago
6

Angela deposited 2,400 into her bank account each year that she keeps her money in the bank, she will earn 3%. At the end of thr

ee years, how much money will she have earned of interest?
Mathematics
2 answers:
IrinaVladis [17]3 years ago
6 0
The answer is 2622.524
nevsk [136]3 years ago
3 0
The answer is 216 because 2400 x .03 is 72 and then multiply that by 3
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nalin [4]

Answer:

About 2105.98

Step-by-step explanation:

31% of 3354 is 1039.74

3354-1039.74=2314.26

9% of 2314.26 is 208.2834

2314.26-2018.2834=2105.9766

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3 years ago
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Which system of the equation is represents by the graph?<br><br><br>​
pashok25 [27]
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2 years ago
8th Grade Math Equation. Please help! I accept any type of help!
muminat

Hello from MrBillDoesMath!

Answer:

Positive x-intercept =  + sqrt(3)

Negative x-intercept = - sqrt(3)


Discussion:

Generally, the x-intercept of a function g(x) occurs where g(x) = 0. In our case this is

g(x) = 0   =>

3x^2 - 9 = 0     =>                         (add 9 to both sides of the equation)

3 x^2      = 9    =>                         (divide both sides by 3)

x^2 = 9/3 = 3  =>

x = +\- sqrt (3)

Positive x-intercept =  + sqrt(3)

Negative x-intercept = - sqrt(3)



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5 0
3 years ago
How would I do this at the bottom it says solution
Jlenok [28]

Answer:

all you have to do is graph them but put them in y=mx+b form first, the coordinates is the solution

4 0
3 years ago
Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find
Papessa [141]

Answer:

1) \text{P(at least one boy and one girl)}=\frac{3}{4}

2) \text{P(at least one boy and one girl)}=\frac{3}{8}

3) \text{P(at least two girls)}=\frac{1}{2}

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To  Find : The probability of each event.  

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)        

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

1) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, BGG, GBB, GBG, GGB=6

\text{P(at least one boy and one girl)}=\frac{6}{8}

\text{P(at least one boy and one girl)}=\frac{3}{4}

2) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, GBB=3

\text{P(at least one boy and one girl)}=\frac{3}{8}

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

\text{P(at least two girls)}=\frac{4}{8}

\text{P(at least two girls)}=\frac{1}{2}

4 0
3 years ago
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