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enot [183]
2 years ago
10

A cab company charges according to the following rate chart. Which graph correctly represents the charge, y, in dollars for a ca

b ride of x miles? Cab Rates by Mile Miles Charge Flag drop fee (0 miles) $5.00 g miles $1.00 per mile miles $2.00 per mile for each mile over 10
Mathematics
1 answer:
77julia77 [94]2 years ago
4 0

The graph is the one that correctly represents the linear piece-wise function is the first graph.

<h3>How to solve for the graph</h3>

First we have a linear function as

Mx + b

mc= slope, this is the rate of change, how y changes as x changes by 1.

b = y-intercept, y value as x = 0

y = 5 + x

x ≤ 10

at 10 we have 5 + 10 = 15

at 2 dollars

y = 15 + 2(x - 10)

at 14

y = 15 + 2(14 - 10)

15 + 2*4

= 23

Hence we can conclude that the first graph here is the correct one.

Read more on graphs here:

brainly.com/question/22295833

#SPJ1

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$5 box of cereal: 40% discount?
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4 0
3 years ago
Which of the following linear expressions CANNOT be factored?
Rzqust [24]

It's really easy lol the answer is A) 15x+22

7 0
3 years ago
Read 2 more answers
What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?
Trava [24]

Answer:

\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}

Step-by-step explanation:

The explicit formula for a geometric sequence:

a_n=a_1r^{n-1}

a_n - n-th term

a_1 - first term

r - common ratio

r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}

We have

a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...

The common ratio:

r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}

<h2>It's not a geometric sequence.</h2>

If a_3=-\dfrac{1}{16} then the common ratio is r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}

Put to the explicit formula:

a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}

Put a_n=\dfrac{1}{1024} and solve for <em>n </em>:

-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1

\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6

5 0
3 years ago
The average of Aaron's three test scores must be at least 93 to earn an A in the class. Aaron scored 89 on the first
victus00 [196]

Answer:

Aaron must obtain a 96 or higher to achieve the desired score to earn an A in the class.

Step-by-step explanation:

Given that the average of Aaron's three test scores must be at least 93 to earn an A in the class, and Aaron scored 89 on the first test and 94 on the second test, to determine what scores can Aaron get on his third test to guarantee an A in the class, knowing that the highest possible score is 100, the following inequality must be written:

93 x 3 = 279

89 + 94 + S = 279

S = 279 - 89 - 94

S = 96

Thus, at a minimum, Aaron must obtain a 96 to achieve the desired score to earn an A in the class.

4 0
3 years ago
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