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amm1812
1 year ago
8

What book has the solution in it?

Mathematics
1 answer:
Drupady [299]1 year ago
3 0

Answer:

Book 3

Step-by-step explanation:

So we have four statements:

1: Book 1 or Book 2

2: Book 3 or Book 4

3: Book 4

4: Not Book 3

We also have the condition that only 1 of the statements are correct, and more important, the other 3 are incorrect.

So it may be a bit difficult to see at first, but the solution, has to be book 3. The reason for this is if we assume statement 1, statement 2, or statement 3 is true, that would imply that the statement 4 is false, meaning the solution is in book 3.

If we assume that statement 2 is true, then statement 4 is false, meaning that book 3 has the solution, which aligns statement 2. It also aligns with statement 1 being false, because it's not book 1 or 2, and it also aligns with statement 3 being false, because the solution is not in book 4.

Let's look at why assuming any other statement to be true, leads to contradictions.

So let's assume the first statement is true, this means the solution is book 1 or 2. But this means the statement 4 is false, meaning book 3 has the solution. This contradicts the first statement which we assume is true, thus the first statement is not true.

Let's now assume the third statement is true, this means statement four is false meaning it's book 3, but this contradicts the third statement which says it's book 4. Thus this statement cannot be true

Let's assume the last option is true, this means book 3 has no solution, and since all the other are false, book 4 has no solution, book 3 or 4 has  no solution, book 1 or 2 has no solution either. This means that none of the books have solutions, and assuming one of the books does have a solution, this statement cannot be true.

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Every female bear has 3 baby cubs. What is the constant of proportionality for the ratio of cubs to female bears? (4 points)
andrezito [222]

Answer:

3:1 ratio

Step-by-step explanation:

5 0
3 years ago
A palm tree casts a shadow that is 28 feet long. A 6 foot sign casts a shadow that is 8 feet long. How tall is the palm tree? Se
alukav5142 [94]

Answer:

21

Step-by-step explanation:

28/x=8/6

oopsie if im wrong

4 0
3 years ago
You order two tacos and a salad. the salad costs 2.50.you pay 8% sales tax and leave a $3 tip. you pay a total of 13.80 how much
riadik2000 [5.3K]
Given:Price of one taco = x; price of 2 tacos = 2xPrice of salad = $2.50Sales tax = 8% of the combined price of two tacos and a salad, namely .08(2x + 2.50)Tip = constant fee = $3.00Total bill = $13.80 Therefore the equation becomes
2x + 2.50 + .08(2x + 2.50) + 3 = 13.80 Solutions: 2x + 2.50 + .16x + .20 + 3 = 13.80 (using the distributive property to multiply 2x and 2.5 by .08).2.16x + 2.70 + 3 = 13.80 (combining like terms)2.16x + 5.70 = 13.80 (combining like terms)2.16x + 5.70 = 13.80 - 5.70 (subtraction property of equality)2.16x = 8.10x = 8.10/2.16 = 3.75 (division property of equality)
The cost of a single taco is $3.75
3 0
3 years ago
Given: BC bisects DBE. Prove: ABD is congruent to ABE
Arada [10]

Answer:

See below

Step-by-step explanation:

BC bisects <DBE and if AC is a straight line then you have that:

<ABD + <DBC = 180 (straight angle because of line AC)

<ABE + <CBE = 180 ( straight angle because of line AC)

Because BC bisects <DBE =>   < DBC = <CBE

So <ABD and <ABE must be the same to both sum 180 when added < DBC

7 0
3 years ago
The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c
valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is 10.4 \:cm^2

Step-by-step explanation:

The area of a rectangle with length L and width W is A= L\cdot W so the differential of <em>A</em> is

dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W

\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L so

dA=W\Delta L+L \Delta W

We know that each error is at most 0.1 cm, we have |\Delta L|\leq 0.1, |\Delta W|\leq 0.1. To find the maximum error in the calculated area of the rectangle we take \Delta L = 0.1, \Delta W = 0.1 and L=55, W=49. This gives

dA=49\cdot 0.1+55 \cdot 0.1

dA=10.4

Thus the maximum error in the calculated area of the rectangle is 10.4 \:cm^2

4 0
3 years ago
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