What is the slope of the line graphed below?

Mathematics

1 answer:

Dafna11 [192]1 year ago

4 0

Answer:

-3

Step-by-step explanation:

slope (m) = (y2 - y1)/(x2 - x1)

(1, 1) --> 1 = x1, 1 = y1

(2, -2) --> 2 = x2, -2 = y2

(-2 - 1) / (2 - 1) = -3 / 1 = -3

therefore, the slope is -3

hope this helps <3

You might be interested in

What do you think ? compared to bottoms up method: better, Worse, the same or something Else?

Leya [2.2K]

Idk what u mean.......

3 0

3 years ago

As shown in the graph, ΔGHI ≅ ΔG'H'I', since this is a vertical shift, and ΔG'H'I' ≅ ΔG''H''I'', since this is a horizontal shif

77julia77 [94]

D) (X,Y) → (x + 4, y - 5).
HOPE THIS HELPED :-)

4 0

3 years ago

Please help me IDk this at all!!!!

jasenka [17]

It would help if you find common denominator... 12
so 1/3 times 4 both the numerator and denominator
4/12

and 3/4 times by 3 both the numerator and denominator
9/12

the recipe calls for 4/12 cup of oil and you have 9/12

two batches would be 8/12 cups of oil, you have 9/12 that is just enough for the recipe for two batches...

now to simplify it again, 1/3 + 1/3 = 2/3 and 2/3 is less than 3/4
the answer would be the upper right

3 0

3 years ago

Read 2 more answers

NO LINKS!!!! Find the equation of the circle below

inysia [295]

Answer:

$(x+3)^2+(y-2)^2=9$

Step-by-step explanation:

Equation of a circle

$(x-a)^2+(y-b)^2=r^2$

where:

(a, b) is the center
r is the radius

From inspection of the diagram, the center of the circle appears to be at point (-3, 2), although this is not very clear. Therefore, a = -3 and b = 2.

Substitute these values into the general form of the equation of a circle:

$\implies (x-(-3))^2+(y-2)^2=r^2$

$\implies (x+3)^2+(y-2)^2=r^2$

Again, from inspection of the diagram, the maximum vertical point of the circle appears to be at y = 5. Therefore, to calculate the radius, subtract the y-value of the center point from the y-value of the maximum vertical point:

⇒ radius (r) = 5 - 2 = 3

Substitute the found value of r into the equation:

$\implies (x+3)^2+(y-2)^2=3^2$