Answer:
Width of the pool = 15 yards
Step-by-step explanation:
Given that:
Length of diagonal of swimming pool = 29 yards
Length of the pool = 25 yards
Let,
w be the width.
This will form a right angled triangle where the diagonal will be hypotenuse.
Using Pythagorean theorem;
Taking square root on both sides
Rounding off to nearest whole number
w = 15 yards
Hence,
Width of the pool = 15 yards
Answer: 99.5
Step-by-step explanation:
398 ÷ 4
5x+3y+6x+9y
All you'd need to do is combine like terms. So add 5x to 6x and add 3y to 9y.
(5x+6x)+(3y+9y)
Final Answer: 11x + 12y
The answer is 1/14. -3/7 x -1/6. 3 crosses 6 2 time so you are left with -1/7 x -1/2 that is 1/14
Ratios of Area of the two squares = 25:9
So then let the areas be A1 = 25A and A2 = 9A, A is common element
Side of the smaller area S2 = 30 meters
Area of the smaller square A2 = 30 x 30 = 900
We have area of smaller square as 9A = 900 => A = 100
Area of the large square = 25A = 25 x 100 = 2500.
Hence S1^2 = 2500 => S1 = 50 meters which is 20 meters longer than the
side of the smaller square.