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skelet666 [1.2K]
2 years ago
14

F∧-1(-2) i need help solving this f to -1 power times -2

Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
4 0

The solution is f².

<h3>How to solve for this</h3>

The question that we have here is of the form f to -1 power times -2. To have a better graphic image we can rewrite it as

f^-^1^(^-^2^)

Now we have to multiply the powers -1 and -2

Remember that in the rules of mathematics, the solution for -1 and -1 = 1

This tells us that - * - = +

Hence we would have -1 * -2

= 2

Therefore the power would be f²

<h3>How do you simplify exponents and powers?</h3>

In order to carry out the simplification of exponents what you have to do would be the multiplication of the exponents that are in the question. The base of the question remains unchanged.

For example, (2³)⁵ = 2³ˣ⁵ = 2¹⁵. For any positive number x and integers a and b: (x^a)^b = x^a^.^b

The exponents here are the numbers that are written above the base. They usually tell us how many times the base would have to be multiplied by itself to get a  solution.

Read more on multiplication of powers here:

brainly.com/question/26130878

#SPJ1

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[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

7 0
3 years ago
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