Answer:
I honestly have no clue.
Step-by-step explanation:
I honestly have no clue.
 
        
             
        
        
        
Answer:
<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>p</em><em>/</em><em>6</em><em>-4</em><em>/</em><em>5</em><em>.</em>
<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em>
 
        
                    
             
        
        
        
The values of x that will give the quadratic equation no real number solutions are -5 and 9
<h3>What are real roots of a quadratic equation?</h3>
Real roots of a quadratic equation are values of x, whose numbers can be represented on a number line.
Analysis:
We have - +3x +c = 0
 +3x +c = 0
 - 4ac  is called the discriminant of a quadratic equation.
 - 4ac  is called the discriminant of a quadratic equation.
if  - 4ac  < 0, then the quadratic equation has no real root.
 - 4ac  < 0, then the quadratic equation has no real root.
where a = -1, b = 3 c = c
 -4(-1)c < 0
 -4(-1)c < 0
9 + 4c < 0
4c < -9
c < -9/2
Which means values lower than -9/2 would give the solution no real root.
From, the options,  only -5 would give no real solution, since it is lower than -9/2.
Learn more about real roots of a quadratic equation: brainly.com/question/7784687
#SPJ1