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Answer:
<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>p</em><em>/</em><em>6</em><em>-4</em><em>/</em><em>5</em><em>.</em>
<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em>
The values of x that will give the quadratic equation no real number solutions are -5 and 9
<h3>What are real roots of a quadratic equation?</h3>Real roots of a quadratic equation are values of x, whose numbers can be represented on a number line.
Analysis:
We have - +3x +c = 0
- 4ac is called the discriminant of a quadratic equation.
if - 4ac < 0, then the quadratic equation has no real root.
where a = -1, b = 3 c = c
-4(-1)c < 0
9 + 4c < 0
4c < -9
c < -9/2
Which means values lower than -9/2 would give the solution no real root.
From, the options, only -5 would give no real solution, since it is lower than -9/2.
Learn more about real roots of a quadratic equation: brainly.com/question/7784687
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