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Alika [10]
2 years ago
8

Describe how the pH of anti-acid powder can be determined

Chemistry
1 answer:
alexdok [17]2 years ago
5 0

This can be done by Crystallization, filtration or sublimation.

Ammonium chloride can be seperated from a mixture Sodium chloride and ammonium chloride by the process of sublimation. Ammonium chloride can be sublimed whereas Sodium chloride can be sublimed. When a mixture of sodium chloride and ammonium is heated.

to learn more about Methods of seperation click here brainly.com/question/5441290

#SPJ9

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52.0 g of LiCl represents ______ moles of LiCl. A) 0.88 Eliminate B) 1.23 C) 1.51 D) 2.45
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If a molecule can hydrogen bond, does it guarantee that it will have a higher boiling point than a molecule that cannot? Explain
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Answer:

a): not necessarily due to London Dispersion Forces and dipole-dipole interactions.  

b): not necessarily due to London Dispersion Forces.

Explanation:

There are three major types of intermolecular interaction:

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The melting point of a substance is a result of all three forces, combined.

Note that the more electrons in each molecule, the stronger the London Dispersion Force. Generally, that means the more atoms in each molecule, the stronger the London dispersion force. The strength of London dispersion force between large molecules can be surprisingly strong.

For example, \rm H_2O (water) molecules are capable of hydrogen bonding. The melting point of \rm H_2O at \rm 1\; atm is around 0 \; ^{\circ}\rm C. That's considerably high when compared to other three-atom molecules.

In comparison, the higher alkane hexadecane (\rm C_{16}H_{34}, straight-chain) isn't capable of hydrogen bonding. However, under a similar pressure, hexadecane melts at around 18\; ^{\circ}\rm C above the melting point of water. The reason is that with such a large number of atoms (and hence electrons) per molecule, the London dispersion force between hexadecane molecules could well be stronger than that the hydrogen bonding between water molecules.

Similarly, the dipole moments in HCl (due to the highly-polar H-Cl bonds) are much stronger than those in hexadecane (due to the C-H bonds.) However, the boiling point of hexadecane under standard conditions is much higher (at around 287\; \rm ^\circ C than that of HCl.

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lubasha [3.4K]
<span> C12H4Cl6 + 23 O2 + 2 H2O → 24 CO2 + 12 HCl </span>

<span>(a) </span>
<span>(13.5 mol O2) x (2 mol H2O / 23 mol O2) = 1.17 mol H2O </span>

<span>(b) </span>
<span>(17.6 mol H2O) x (12 mol HCl / 2 mol H2O) x (36.4611 g HCl/mol) = 3850 g HCl </span>

<span>(c) </span>
<span>(90.4 g HCl) / (36.4611 g HCl/mol) x (24 mol CO2 / 12 mol HCl) = 4.96 mol CO2 </span>

<span>(d) </span>
<span>(106.01 g CO2) / (44.00964 g CO2/mol) x (2 mol C12H4Cl6 / 24 mol CO2) x (360.8782 g C12H4Cl6/mol) = </span>
<span>72.4 g C12H4Cl6 </span>

<span>(e) </span>
<span>(4.2 kg C12H4Cl6) / (360.8782 g C12H4Cl6/mol) x (12 mol HCl / 2 mol C12H4Cl6) x (36.4611 g HCl/mol) = </span>
<span>2.5 kg HCl</span>
4 0
3 years ago
Read 2 more answers
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