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Law Incorporation [45]

3 years ago

5

Samuel is boiling water to cook pasta for dinner. The water in the pot starts at 67°F, and the temperature increases by 13°F per

minute. How long does it take for the water to reach 145°F? Write and solve an equation to find the answer. minutes

1 answer:

Vladimir79 [104]3 years ago

8 0

Answer:

It will take the pot 6 minutes to reach 145 degrees

Step-by-step explanation:

If you add 13 to 67 six times then you will get 145

hope this helps

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1) f(x) = - x2 + 4x - 10<br> Find f(5)

Natali5045456 [20]

Substitute the x with 5
-(5)2 + 4(5) - 10 = 0

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3 years ago

If the 7th of an AP is equal to 11 times the 11th term, find the 18th term

Zina [86]

Answer:

-33 or 33

Step-by-step explanation:

The seventh term of an AP is written as:

$a + 6d$

The eleventh term of an AP is written as:

$a + 10d$

If the 7th term is 11 times the 11th term, then;

$a + 6d = 11(a + 10d)$

Expand to get:

$a + 6d = 11a + 110d$

$11a - a = 6d - 110d$

$10a = - 104d$

$\frac{a}{d} = - \frac{104}{10}$

$\frac{a}{d} = - \frac{52}{5}$

We must have a=-52 and d=5

Or

a=52 and d=-5

For the first case, the 18th term is :

$- 52 + 5 \times 17 = 33$

For the second case,

$52 - 5 \times17 = - 33$

3 0

4 years ago

If (5⁴)m = 5 ¹²,what is the value of m<br> 2<br><br> 3<br><br> 5<br><br> 8

Lapatulllka [165]

The correct answer is: [B]: " 3 " .
_______________________________________________
Note:
_______________________________________________
The question asks:
_______________________________________________
If (5⁴)ᵐ = 5¹² ; then what is "m" ?

Note the following property of exponents:
________________________________________________
(xᵃ)ᵇ = x⁽ᵃ*ᵇ⁾ ; a≠0 ; b ≠ 0 ;

Then, (5⁴)³ = 5⁽⁴ * ³⁾ = 5¹² .

So, "12 ÷ 4 = 3" .
________________________________________________
The answer is: "m = 3" ; which is: Answer choice: [B] .
________________________________________________

5 0

4 years ago

Solve the equations by substitution method: A. 2x-y-3=0 and 3x+4y=65.

PSYCHO15rus [73]

Step-by-step explanation:

$\sf 2x-y-3=0\dots \dots (1)$

$\sf 3x+4y=65 \\ \implies\sf 3x+4y-65=0 \dots\dots(2)$

from eq (1)

${:}\longrightarrow$ $\sf 2x-y-3=0$

${:}\longrightarrow$ $\sf 2x-3=y$

${:}\longrightarrow$ $\sf y=2x-3 \dots\dots(3)$

Substitute the value in eq(2)

${:}\longrightarrow$ $\sf 3x+4y-65=0$

${:}\longrightarrow$ $\sf 3x +4 (2x-3)-65=0$

${:}\longrightarrow$ $\sf 3x+8x-12-65=0$

${:}\longrightarrow$ $\sf 11x-77=0$

${:}\longrightarrow$ $\sf 11x=77$

${:}\longrightarrow$ $\sf x={\dfrac {77}{11}}$

${:}\longrightarrow$ $\sf x=7$

Substitute the value in eq (3)

${:}\longrightarrow$ $\sf y=2x-3$

${:}\longrightarrow$ $\sf y=2 (7)-3$

${:}\longrightarrow$ $\sf y=14-3$

${:}\longrightarrow$ $\sf y=11$

$\therefore$ ${\underline{\boxed{\bf (x,y)=(7,11)}}}$

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HACTEHA [7]

Answer:

$60

Step-by-step explanation:

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