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astraxan [27]
2 years ago
10

The first moment of the total cross-sectional area taken about the neutral axis must be?

Physics
2 answers:
bekas [8.4K]2 years ago
7 0

The first moment of the total cross sectional area taken about the neutral axis must be zero.

As with non-composite beams, the neutral axis (NA) is the location where the bending stress is zero. The location of the NA depends on the relative stiffness and size of each of the material sections.

Generally, the NA location is determined relative to the bottom surface of the beam. However, this is not mandatory, and the location can be relative to any location. If the bottom is used, then the NA axis is a distance "h"

The distance h can be determined by recalling that the stresses through the cross section must be in equilibrium.

learn more about neutral axis from here: brainly.com/question/28167877

#SPJ4

muminat2 years ago
7 0

The first moment of the total cross-sectional area taken about the neutral axis must be zero.

A member that resists bending has a neutral axis in its cross-section along which there are no longitudinal stresses or strains. The neutral axis lies at the geometric centroid if the section is symmetric, isotropic, and does not curve before a bend. The neutral axis is not under any strain. Therefore, the neutral axis has no bending moment. Because the neutral axis is not affected by the applied stresses, there is no bending stress. At the neutral axis, no stress is created. The line in the cross-section of a beam where there is neither longitudinal compression nor tensile stress is known as the neutral axis for that beam. The neutral axis is typically regarded in the study of wood beams to be at the centroid of the beam.

Learn more about  cross-sectional  here brainly.com/question/23377829

#4243.

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A force does work on an object if a component of the force is
IrinaK [193]

Answer:

A force does work on an object if a component of the force is parallel to the displacement of the object.

Explanation:

Work, a measurement of energy is said to be done when a force applied to an object results in the movement of that object to a certain distance and direction. Force is the act of push or pulls occurs on an object as a result of the interaction between that object with another one and displacement is the distance and direction covered by that object as a result of the force applied on it.

The work done (W) by a constant force (F) is equal to the product of the force in the direction of displacement of the object and the distance (d) moved by the object i.e., W = F * d.

The angle between the displacement and the force is θ, then the work done, W = Fd cos θ  ........ (1)

Positive work - Force acts in the same direction with respect to the displacement of the object. Here, θ is zero, so cos θ i.e., cos 0 is 1. Therefore, from the equation (1), W = Fd (i.e., work done by the force is positive).

Negative work - Force acts in the opposite direction with respect to the displacement of the object.  Here, θ is 180°, so cos θ i.e., cos 180° is -1. Therefore, from the equation (1), W = -Fd (i.e., work done by the force is negative).

If a force is applied to an object and it does not move, then the work done is zero i.e., W = F * 0 = 0. Also, if the force and displacement are at right angle to each other, then θ is 90°. Therefore, from the equation (1), W = 0 since cos 90° is zero.

7 0
4 years ago
An 7.9 kg crate is pulled 5.5 m up a 30∘ incline by a rope angled 19 ∘ above the incline. The tension in the rope is 140 N and t
dedylja [7]

Answer:

Wt= 0.73kJ, Wg=0.21kJ Wn= 0J

(B) Wf= 0.096kJ

Explanation:

See attachment below.

5 0
4 years ago
Why did one-half of the Moon's surface remain
choli [55]

Answer:

The moon's revolution around its axis and the moon's revolution around the Earth take the same time, approximately 27 days. That causes one side of the Moon to always face the Earth while the other side always faces away from the Earth. That is why it took probes to go into space to photograph the side that is never visible from Earth for people to be able to see it.

6 0
3 years ago
Drag and drop the terms at the left to match the appropriate descriptions at the right. ResetHelp Visual acuity Emmetropia Accom
Lubov Fominskaja [6]

Answer: Visual acuity: sharpness of vision.

Myopia: nearsightedness

Refraction: bending of light rays.

Emmetropia: normal vision.

Accommodation: changes the shape of the eye lens to focus light on the retina.

Presbyopia: age-related farsightedness due to loss of elasticity in the lens.

Astigmatism: reduction in visual acuity due to changes in the cornea or lens.

Hyperopia: farsightedness

Myopia and hyperopia are refractive errors of the eye.

Presbyopia occurs in old age people.

Explanation:

Visual acuity: It can be defined as the inability to observe the details of shape of the object. Person loses sharpness in vision.

Myopia: It is a defect in vision in which person is able to observe the near by objects clearly but not able to see the distant objects.

Refraction: It can be defined as the bending of beam of light when it passes through from one substance to another.

Emmetropia: It is a vision without any defect.

Accommodation: It is the ability of the eye to adjust its focal length and adjusting the light on focus.

Presbyopia: It can be defined as the loss of ability of eye to focus on the object. It occurs in old age.

Astigmatism: It is a refractive error in which the eye does not focus light on retina.

Hyperopia: It is also called as farsightedness. Distant objects can be seen clearly but nearby appears blurry.

5 0
3 years ago
A plane travels 1743 KM in 2 hours 30 minutes. How fast was the plane traveling?
Advocard [28]

Answer:

v=697.2km/h

Explanation:

Hello.

In this case, since the velocity is computed via the division of the distance traveled by the elapsed time:

V=\frac{d}{t}

The distance is clearly 1743 km and the time is:

t=2h+30min*\frac{1h}{60min} =2.5h

Thus, the velocity turns out:

v=\frac{1743km}{2.5h}\\ \\v=697.2km/h

Which is a typical velocity for a plane to allow it be stable when flying.

Best regards.

5 0
3 years ago
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