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Juliette [100K]
3 years ago
7

Drag and drop the terms at the left to match the appropriate descriptions at the right. ResetHelp Visual acuity Emmetropia Accom

modation Astigmatism Myopia Hyperopia Presbyopia Refraction : normal vision. : reduction in visual acuity due to irregularities in the cornea or lens. : farsightedness. : nearsightedness. : age-related farsightedness due to loss of elasticity in the lens. : sharpness of vision. : bending of light rays. : changes the shape of the eye lens to focus light on the retina.
Physics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0

Answer: Visual acuity: sharpness of vision.

Myopia: nearsightedness

Refraction: bending of light rays.

Emmetropia: normal vision.

Accommodation: changes the shape of the eye lens to focus light on the retina.

Presbyopia: age-related farsightedness due to loss of elasticity in the lens.

Astigmatism: reduction in visual acuity due to changes in the cornea or lens.

Hyperopia: farsightedness

Myopia and hyperopia are refractive errors of the eye.

Presbyopia occurs in old age people.

Explanation:

Visual acuity: It can be defined as the inability to observe the details of shape of the object. Person loses sharpness in vision.

Myopia: It is a defect in vision in which person is able to observe the near by objects clearly but not able to see the distant objects.

Refraction: It can be defined as the bending of beam of light when it passes through from one substance to another.

Emmetropia: It is a vision without any defect.

Accommodation: It is the ability of the eye to adjust its focal length and adjusting the light on focus.

Presbyopia: It can be defined as the loss of ability of eye to focus on the object. It occurs in old age.

Astigmatism: It is a refractive error in which the eye does not focus light on retina.

Hyperopia: It is also called as farsightedness. Distant objects can be seen clearly but nearby appears blurry.

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1.The lunch lady pushes a 100 kg zombie with 300 N of force. How much is the zombie accelerated?
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1. A=3.00m/s  2.m=50kg

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two astronauts are taking a spacewalk outside the International Space Station the first astronaut has a mass of 64 kg the second
Fittoniya [83]

Answer:

Approximately 0.88\; {\rm m \cdot s^{-1}} to the right (assuming that both astronauts were originally stationary.)

Explanation:

If an object of mass m is moving at a velocity of v, the momentum p of that object would be p = m\, v.

Since momentum of this system (of the astronauts) conserved:

\begin{aligned} &(\text{Total Final Momentum}) \\ &= (\text{Total Initial Momentum})\end{aligned}.

Assuming that both astronauts were originally stationary. The total initial momentum of the two astronauts would be 0 since the velocity of both astronauts was 0\!.

Therefore:

\begin{aligned} &(\text{Total Final Momentum}) \\ &= (\text{Total Initial Momentum})\\ &= 0\end{aligned}.

The final momentum of the first astronaut (m = 64\; {\rm kg}, v = 0.8\; {\rm m\cdot s^{-1}} to the left) would be p_{1} = m\, v = 64\; {\rm kg} \times 0.8\; {\rm m\cdot s^{-1}} = 51.2\; {\rm kg \cdot m \cdot s^{-1}} to the left.

Let p_{2} denote the momentum of the astronaut in question. The total final momentum of the two astronauts, combined, would be (p_{1} + p_{2}).

\begin{aligned} & p_{1} + p_{2} \\ &= (\text{Total Final Momentum}) \\ &= (\text{Total Initial Momentum})\\ &= 0\end{aligned}.

Hence, p_{2} = (-p_{1}). In other words, the final momentum of the astronaut in question is the opposite of that of the first astronaut. Since momentum is a vector quantity, the momentum of the two astronauts magnitude (51.2\; {\rm kg \cdot m \cdot s^{-1}}) but opposite in direction (to the right versus to the left.)

Rearrange the equation p = m\, v to obtain an expression for velocity in terms of momentum and mass: v = (p / m).

\begin{aligned}v &= \frac{p}{m} \\ &= \frac{51.2\; {\rm kg \cdot m \cdot s^{-1}}}{64\; {\rm kg}} && \genfrac{}{}{0}{}{(\text{to the right})}{} \\ &\approx 0.88\; {\rm m\cdot s^{-1}} && (\text{to the right})\end{aligned}.

Hence, the velocity of the astronaut in question (m = 58.2\; {\rm kg}) would be 0.88\; {\rm m \cdot s^{-1}} to the right.

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2 years ago
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