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3 years ago

How many moles of copper are needed to react with sulfur to produce 0.25 moles of copper (I) sulfide

1 answer:

7 0

Copper react with sulfur to produce copper (1) sulfide according to the following equation
2Cu + S ----> CU2S
from the equation above 2 moles of copper react with 1 mole of Sulfur to produce 1 mole of copper (1) sulfide

therefore the mole ratio of Cu to CU2S is 2:1 therefore the moles of copper is 0.25 x 2= 0.5 moles

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Write a balanced equation for the single-replacement oxidation-reduction reaction described, using the smallest possible integer

jeyben [28]

Answer:

$\rm Cl_2 + 2\; KBr \to Br_2 + 2\; KCl$ .

One chlorine molecule reacts with two formula units of (aqueous) potassium bromide to produce one bromine molecule and two formula units of (aqueous) potassium chloride.

Explanation:

<h3>Formula for each of the species</h3>

Start by finding the formula for each of the compound.

Both chlorine $\rm Cl$ and bromine $\rm Br$ are group 17 elements (halogens.) Each
On the other hand, potassium $\rm K$ is a group 1 element (alkaline metal.) Each

Therefore, the ratio between $\rm K$ atoms and $\rm Br$ atoms in potassium bromide is supposed to be one-to-one. That corresponds to the empirical formula $\rm KBr$ . Similarly, the ratio between

The formula for chlorine gas is $\rm Cl_2$ , while the formula for bromine gas is $\rm Br_2$ .

<h3>Balanced equation for the reaction</h3>

Write down the equation using these chemical formulas.

$\rm ?\; Cl_2 + ?\; KBr \to ?\;Br_2 + ?\; KCl$ .

Start by assuming that the coefficient of compound with the largest number of elements is one. In this particular equation, both $\rm KBr$ and $\rm KCl$ features two elements each.

Assume that the coefficient of $\rm KCl$ is one. Hence:

$\rm ?\; Cl_2 + 1 \; KBr \to ?\;Br_2 + ?\; KCl$ .

Note that $\rm KBr$ is the only source of $\rm K$ and $\rm Br$ atoms among the reactants of this reaction.

There would thus be one $\rm K$ atom and one $\rm Br$ atom on the reactant side of the equation.

Because atoms are conserved in a chemical equation, there should be the same number of $\rm K$ and $\rm Br$ atoms on the product side of the equation.

In this reaction, $\rm Br_2$ is the only product with $\rm Br$ atoms.

One $\rm Br$ atom would correspond to $0.5$ units of $\rm Br_2$ .

Similarly, in this reaction, $\rm KCl$ is the only product with $\rm K$ atoms.

One $\rm K$ atom would correspond to one formula unit of $\rm KCl$ .

Hence:

$\displaystyle \rm ?\; Cl_2 + 1 \; KBr \to \frac{1}{2}\;Br_2 + 1\; KCl$ .

Similarly, there should be exactly one $\rm Cl$ atom on either side of this equation. The coefficient of $\rm Cl_2$ should thus be $0.5$ . Hence:

$\displaystyle \rm \frac{1}{2}\; Cl_2 + 1 \; KBr \to \frac{1}{2}\;Br_2 + 1\; KCl$ .

That does not meet the requirements, because two of these coefficients are not integers. Multiply all these coefficients by two (the least common multiple- LCM- of these two denominators) to obtain:

$\displaystyle \rm 1\; Cl_2 + 2 \; KBr \to 1\;Br_2 + 2\; KCl$ .

7 0

3 years ago

How many particles are in 4g of NaCl? (1mol of NaCl = 58g) – 2 step conversion

oksian1 [2.3K]

Answer:

4.16 * 10²⁴ particles

Explanation:

1. We convert from grams to moles

4 g NaCl / 58 g of NaCl = 0.0689655172 moles

-> 0.0690 moles

2. Now we will convert from moles to particles by multiplying by avogadro's number..

0.0690 * 6.022 *10²³ = 4.15518 * 10²⁴ particles or 4.16 * 10²⁴ particles

4 0

3 years ago

Hydrogen gas can combine with oxygen gas under certain conditions to form water. Which name is a general term for water in this

antoniya [11.8K]

Product

Explanation:

Water in this reaction is called the product of the reaction.

The product is the new kind of matter formed as a result of a chemical change. They are produced from the combination of reactants.

2H₂ + O₂ → 2H₂O

Reactants Products

A chemical reaction involves the combination of chemical species to form a product. The type of reaction above is a called synthesis reaction.

learn more:

Chemical equation brainly.com/question/5247791

#learnwithBrainly

8 0

3 years ago

Example: Make 100 mL 0.05 M NaOH from a 1.5 M solution.<br>0.05 * 100 = 1.5 * ?

____ [38]

Answer:

3.33

Explanation:

M= 0.05*100/1.5= 3.33

4 0

3 years ago

When two aqueous solutions are combined the reaction forms a solid that settles out of solution. What is this solid called?

Rama09 [41]

During the chemical reaction, the solid substance that is insoluble formed during the combination of two aqueous solutions is called a precipitate. The answer is letter C. The precipitation reaction occurs when a salt is formed in the reaction of solutions with salts.

6 0

3 years ago