The ionization energy is 1 × 10^-18 J
<h3>What is ionization energy?</h3>
The ionization energy is the energy required to remove an electron from an atom.
We have the following information;
wavelength of the photon = 58.4 nm
Speed of the electron = 2310 × 10^3 m/s
Since;
hv = I + 1/2mv^2
v = c/λ
hc/λ = I + 1/2mv^2
I = hc/λ - 1/2mv^2
I = (6.6 × 10^-34 × 3 × 10^8/58.4 × 10^-9) - (1/2 × 9.11 × 10^-31 × (2310 × 10^3)^2)
I = 1 × 10^-18 J
Learn more about ionization energy: brainly.com/question/16243729
Answer:
H₂O₂
Explanation:
The molecular formula gives the exact number of atoms within a chemical compound.
In this problem:
Mass of O = 32g
Mass of H = 2g
Let us follow this methodical approach to solve the problem:
Elements O H
Mass 32 2
Molar mass 16 1
Number of moles 32/16 2/1
2 2
The molecular formula of the compound is H₂O₂
Answer : The volume of 1 mole of 
and 
gases are the same.
Solution: Given,
Moles of = 1 mole
Moles of = 1 mole
Moles of 
= 2 mole
Formula used for ideal gas is :
P V = n R T
According to the question, the gases are at standard temperature and pressure. So, the volume of gases only depends on the number of moles. This means that the higher the number of moles, higher will be the volume of gas.
The moles of are more than the moles of and . So, the volume of will be more.
And the moles of and are equal. Therefore, their volumes are also equal.
Therefore, the best option is the volume of 1 mole of and gases are the same.
Answer:
The Kinetic Energy is approximately 3 times decreased
Explanation:
A baseball weighs 5.13 oz.
a)What is the kinetic energy, in joules, of this baseball when it is thrown by a major league pitcher at 95.o mi/h?
b) By what factor will the kinetic energy change if the speed of the baseball is decreased to 54.8 mi/h? Express your answer as an integer.
Kinetic Energy (KE)=0.5×mass×velocity ^ 2
Kinetic Energy (KE)=0.5×mass × velocity ^ 2
Joules = kg×m^2/s^2
1 mile = 1609.344 meters
1 hour = 3600 sec
1 Oz = 28.34952 g = 0.02834952 kg
a) KE=0.5×m×v^2
=0.5×(5.13 oz × 0.02834952 kg/1 ounce)×(95 miles/h × 1609.344 m/1 mile × 1 hr/3600 s)^2
=130.761 kg×m^2/s^2 = 130.761 Joules
b) KE=0.5×m×v^2
=0.5×(5.13 oz × 0.02834952 kg/1 ounce)×(54.8 miles/h × 1609.344 m/1 mile × 1 hr/3600 s)^2
=43.51028 kg×m^2/s^2 = 43.51028 Joules
= 130.761 / 43.51028 = 3.00528,
As such the Kinetic Energy is approximately 3 times decreased
