Answer:
The Partial pressure of Xe and Ne will be 4.95 atm and 1.55 atm. The number of moles of Xe and Ne will be 3.13 and 0.981
Explanation:
Let the total pressure of the vessel= 6.5 atm and mole fraction of Xenon= 0.761
As we know,

According to Dalton's Law of partial pressure-

Where,
The pressure of the gas component in the mixture
Mole fraction of that gas component
The total pressure of the mixture

<u>Calculation: </u>
To calculate the number of moles,
PV=nRT


Learn more about Dalton's Law of partial pressure here;
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Answer:
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B
B
I Hope u can understand and it's correct answer
For the purpose, we will use the equation for determining the dissociation constant from concentration and <span>percent of ionization:
Kd = c </span>× α²
α = √(Kd/c) × 100%
Kd = 6.0×10⁻⁷
c(HA) = 0.1M
α = √(6.0×10⁻⁷/0.1) × 100% = 0.23%
So, in the solution, the acid <span>percent of ionization will be just 0.23%.</span>