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likoan [24]
2 years ago
10

Quick algebra 1 question for 10 points!

Mathematics
1 answer:
Maslowich2 years ago
7 0

The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.

<h3>What is the range of a quadratic equation?</h3>

In this case we have a <em>quadratic</em> equation whose domain is stated. The domain of a function is the set of x-values associated to only an element of the range of the function, that is, the set of y-values of the function. We proceed to evaluate the function at each element of the domain and check if the results are in the choices available.

x = - 9

y = (2 / 3) · (- 9)² - 6

y = 48

x = - 6

y = (2 / 3) · (- 6)² - 6

y = 18

x = - 3

y = (2 / 3) · (- 3)² - 6

y = 0

x = 0

y = (2 / 3) · 0² - 6

y = - 6

x = 3

y = (2 / 3) · 3² - 6

y = 0

x = 6

y = (2 / 3) · 6² - 6

y = 18

x = 9

y = (2 / 3) · 9² - 6

y = 48

The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.

To learn more on functions: brainly.com/question/12431044

#SPJ1

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Irina18 [472]

Answer:

22.38 g of silicone-32 will be present in 300 years.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

                                           N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}

where,

N(t) = quantity of the substance remaining

N_0 = initial quantity of the substance

t = time elapsed

t_{1/2} = half life of the substance

From the information given we know:

  • The initial quantity of silicone-32 is 30 g.
  • The time elapsed is 300 years.
  • The half life of silicone-32 is 710 years.

So, to find the quantity of silicone-32 remaining we apply the above equation

N(t)=30\left(\frac{1}{2}\right)^{\frac{300}{710}}=30\left(\frac{1}{2}\right)^{\frac{30}{71}}\approx22.38 \:g

22.38 g of silicone-32 will be present in 300 years.

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3 years ago
The function h is defined by h (x) = 5x + 2
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The correct answer is 42.
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Find the mean, median, and mode of the data set. Round to the nearest tenth. 15, 13, 9, 9, 7, 1, 11, 10, 13, 1, 13 mean = 8.5, m
jasenka [17]

Answer:

Mean = 9.3

Median = 10

Mode = 13

Step-by-step explanation:

To get the mean, you would have to add up all of the numbers (102), then divide how many numbers you have with the numbers added up (9.3). To get the median, you would have to put all of the numbers that you have, in order, from least to greatest and cross off each number, one from each side before getting to the number in the middle (unless if you have an even number; works better with odd numbers, which is easier). To get the mode, you would need to find out which number appears the most, and, if there is more than one, you can put the numbers down. Hope this helps.

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Read 2 more answers
The regression equation Credits = 17.9 − 0.09 Work was estimated from a sample of 21 statistics students. Credits is the number
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Answer:

Step-by-step explanation:

Hello!

Given the regression equation

Credit= 17.9 - 0.09 Work

That was estimated from a sample of n= 21 statistic students.

Y: number of college credits taken

X: number of hours worked per week at an outside job

a)

The estimation for the slope is -0.09

As you see the estimated slope is negative, this means that the association between the two variables is indirect or inverse. Meaning, when the number of Work increases, the number of Credit decreases. (negative regression)

The correct option is: "An increase in the number of hours worked per week decreases the expected number of credits."

b)

The estimation for the intercept is 17.9

In general, the intercept is the estimated average of Y when X=0. You can interpret the intercept of this equation as "the value of Credits earned by a student that does not work outside of school"

The correct option is: " The intercept is meaningful as a student may not have a job outside of school. "

c)

If Work=0, then Credit= 17.9 (As explained in item b)

By replacing the value in the equation: Credit= 17.9 - 0.09 * 0= 17.9

If Work=60, you replace it in the equation and:

Credit= 17.9 - 0.09 Work= 17.9-0.09*60= 12.5

If the student works 60 hs outside of school it is expected that he takes 12.5 college credits.

I hope this helps!

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Answer:

There is no slope

Step-by-step explanation:

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