Question

A cyclist is riding a bicycle whose wheels have a diameter of feet. Suppose the wheels turn at a rate of revolutions per minute.

Answer 1

Answer:

a.2010 rad/min

b.2412 feet/min

Step-by-step explanation:

We are given that

Diameter of wheel,d=2.4 feet

Radius,r=$\frac{d}{2}=\frac{2.4}{2}=1.2feet$

a.Rate=320 rev/minute

1 rev=$2\pi$ radian

320 rev/minute=$320\times 2\pi=640\pi radian/minute$

Where $\pi=3.14$

Angular speed=$640\times 3.14=2010 rad/min$

b.Speed,v=$r\omega$

$v=2010\times 1.2=2412 feet/min$