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2 years ago

A cyclist is riding a bicycle whose wheels have a diameter of feet. Suppose the wheels turn at a rate of revolutions per minute.

Mathematics

1 answer:

SCORPION-xisa [38]2 years ago

5 0

Answer:

a.2010 rad/min

b.2412 feet/min

Step-by-step explanation:

We are given that

Diameter of wheel,d=2.4 feet

Radius,r= $\frac{d}{2}=\frac{2.4}{2}=1.2feet$

a.Rate=320 rev/minute

1 rev= $2\pi$ radian

320 rev/minute= $320\times 2\pi=640\pi radian/minute$

Where $\pi=3.14$

Angular speed= $640\times 3.14=2010 rad/min$

b.Speed,v= $r\omega$

$v=2010\times 1.2=2412 feet/min$

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