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olasank [31]
2 years ago
11

Mannose (C6H12O6) is a simple sugar found in many fruits and vegetables. How many oxygen atoms are in 7. 15 x 10^23 molecules of

mannose?
Chemistry
1 answer:
maxonik [38]2 years ago
6 0

Number of oxygen atoms present in 7.15×10²³ molecules of mannose are 1.92≈2 a m u .

<h3>What is mannose sugar?</h3>

D-mannose is a simple sugar found in many fruits. It is related to glucose. In some cells it occurs naturally in the body.

Mannose is a six-carbon sugar found in a variety of fruits and vegetables. This sugar is not found free in foods. It is a part of polysaccharide chains attached to a variety of proteins.

To calculate number of oxygen atoms present in 7.15×10²³  molecules of mannose-

Since,

1 molecule of oxygen=2.303×10²³ no. of atoms

Here,  total number of molecules of oxygen is 6.

Therefore, 6 molecule of oxygen =6×2.303×10²³÷7.15×10²³

=1.92≈2 a m u .

Hence, the total number of oxygen atoms in 7.15×10²³ molecules of mannose is 1.92 ≈2 a m u.

Learn more about mannose sugar, here:

brainly.com/question/7008130

#SPJ4

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Answer:

NiCO3 (s) + 2H+ (aq) → H2O (l) + CO2 (g) + Ni2+ (aq)

Explanation:

To write the complete ionic equation:

1. Start with a balanced molecular equation.

2. Break all soluble strong electrolytes (compounds with (aq) beside them) into their ions

3. indicate the correct formula and charge of each ion

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8 0
3 years ago
Help help please
ladessa [460]

Substances that exist in solution almost completely as ions are called strong electrolytes. Therefore, the answer is C.

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3 years ago
If the half-life of 37Rb is 4.7x101 years, how long would it take for 0.5 grams of a 2 gram sample to radioactively decay?
k0ka [10]

<u>Answer:</u> The time required will be 19.18 years

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

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We are given:

t_{1/2}=4.7\times 10^1yrs

Putting values in above equation, we get:

k=\frac{0.693}{4.7\times 10^1yr}=0.015yr^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,  

k = rate constant  = 0.015yr^{-1}

t = time taken for decay process = ?

[A_o] = initial amount of the reactant = 2 g

[A] = amount left after decay process =  (2 - 0.5) = 1.5 g

Putting values in above equation, we get:

0.015yr^{-1}=\frac{2.303}{t}\log\frac{2}{1.5}\\\\t=19.18yrs

Hence, the time required will be 19.18 years

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Scilla [17]

Answer:

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