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lorasvet [3.4K]
3 years ago
13

Identify each of the following as an example of either basic research, applied research, or

Chemistry
1 answer:
zvonat [6]3 years ago
8 0

Answer:

A) a new type of refrigerant that is less damaging to the environment is developed.  Applied development

B) a new element is synthesized in a particle accelerator.  Basic development.

C) a computer is redesigned to increase the speed of the computer. Technological development.

Explanation:

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Nezavi [6.7K]

Answer:

yes, albert is better grffffrr#fffffrttt.

Explanation:

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3 years ago
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What would barium do to obtain a noble gas structure?
ExtremeBDS [4]
Ba 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s² → [Xe]6s²

Ba - 2e⁻ → Ba⁺²  [Xe]
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3 years ago
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Something that does not have the ability to react is considered
nasty-shy [4]
Something that does not have the ability to react is considered inert. <span> In chemistry, the term </span>inert<span> is used to describe a substance that is not </span>chemically<span> reactive. Hope this answers the question. Have a nice day.</span>
4 0
4 years ago
n the formation of chloromethane and hydrogen chloride. The overall reaction is 2CH4(g)+3Cl2(g)⟶2CH3Cl(g)+2HCl(g)+2Cl−(g) 2CH4(g
IrinaVladis [17]

Answer:

The total pressure in the flask is 0,619 atm.

Explanation:

For the reaction:

2CH₄(g) + 3Cl₂(g) ⟶ 2 CH₃Cl(g) + 2HCl(g) + 2Cl⁻(g)

The moles of CH₄ in 295 mL at STP are:

n = PV/RT

Where P is pressure (1 atm), V is volume (0,295L), R is gas constant (0,082atmL/molK) and T is temperature (273,15 K)

Replacing, moles of CH₄ are <em>0,0132 moles</em>

In the same way, moles of chlorine are <em>0,0324 moles</em>

As 3 moles of Cl₂ react with 2 moles of CH₄, for a total reaction of 0,0132 moles of CH₄ you need:

0,0132 moles CH₄ × \frac{3 moles Cl_{2}}{2 moles CH_{4}} = <em>0,0198 moles Cl₂. </em>That means that 0,0324-0,0198 = <em>0,0126 moles of Cl₂ are in excess.</em>

As the reaction reaches in 77%, the moles of CH₄ that don't react are:

0,0132×(100%-77%)= <em>3,036x10⁻³ moles of CH₄</em>

Also, the moles of Cl₂ that don't react are:

0,0126 + 0,0198×(100%-77%)= <em>0,0172 moles of Cl₂</em>

The moles produced of each compound are:

0,0132×77% × \frac{2 moles CH_{3}Cl}{2 moles CH_{4}} = <em>0,0102 moles of CH₃Cl -</em><em>that are the same moles of HCl and Cl⁻</em><em>-</em>

Thus, total moles in the flask are:

<em>3,036x10⁻³ moles of CH₄ + 0,0172 moles of Cl₂ + 0,0102 moles of CH₃Cl + 0,0102 moles of HCl + 0,0102 moles of  Cl⁻ = </em><em>0,0507 total moles</em>

As the volume of the flask is 2,00L and the final temperature is 298 K. The total pressure in the flask is:

P = nRT/V

<em>P = 0,619 atm</em>

<em> </em>

I hope it helps!

3 0
4 years ago
Two elements are studied. One has atomic number X and one has atomic number X+2. It is known that element X is a halogen. To wha
vladimir2022 [97]

Answer:

Group 1 (or IA)

Explanation:

If element X is a halogen, then it belongs to the group 17 (or VIIA, under a different notation).

For each extra unit of atomic number, the group number increases by 1. That means that the X+1 element would belong to the group 18 (or VIIIA). <em>The X+2 element would thus belong in the group 1 </em>(or IA) one period higher (higher as in numeric value, not as in position in the periodic table).

7 0
3 years ago
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