In the case of Zn, it is likely eligible for one charge, as its 3d is full, it can lose the electrons from the 4s2 level that it does to become Zn2+.
Iron has 6 electrons in the 3d energy level, which signifies that it would give up 6+2 to get to the next stable energy level. It is much convenient for it to give up the 4s2 and then one more out of the 3d6 to produce Fe2+ and Fe3+ respectively.
Sodium has one electron to give away in the 3s energy level, as soon as it gives its one electron, it will look like Ne. In silver, the 4d10 energy level is full, it can only give up the 5s1 electron easily.
In the case of cobalt, the electrons can be taken from the 4s2 energy level and then one more out of the 3d7 energy level, and after that more and more again. Thus, it can go from +5 to -1 charge, due to much more happening in the 3d7 energy level.
Therefore, cobalt can likely form ions with multiple charges.
I would personally say C. Energy only...
Answer:
All liquid glow products depend on a chemical process known as CHEMILUMINESCENCE to produce their light. Chemiluminesence is a chemical reaction that causes a release of energy in the form of light. To produce this light the electrons in the chemicals become excited and rise to a higher energy level.
To utilise this process glowsticks contain two liquids; hydrogen peroxide and tert-butyl alcohol. When mixed together it is these liquids that create the glow. Fluorescent dyes are also used in the alcohol to alter the colour of the light emitted.
Explanation:
Answer is: the absolute pressure of the air in the balloon is 1.015 atm (102.84 kPa).
n = 0.250 mol; amount of substance.
V = 6.23 L; volume of the balloon.
T = 35°C = 308.15 K; temperature.
R = 0.08206 L·atm/mol·K, universal gas constant.
Ideal gas law: p·V = n·R·T.
p = n·R·T / V.
p = 0.250 mol · 0.08206 L·atm/mol·K · 308.15 K / 6.23 L.
p = 1.015 atm; presure of the air.
Answer:
C.) HOCl Ka=3.5x10^-8
Explanation:
In order to a construct a buffer of pH= 7.0 we need to find the pKa values of all the acids given below
we Know that
pKa= -log(Ka)
therefore
A) pKa of HClO2 = -log(1.2 x 10^-2)
=1.9208
B) similarly PKa of HF= -log(7.2 x 1 0^-4)= 2.7644
C) pKa of HOCl= -log(3.5 x 1 0^-8)= 7.45
D) pKa of HCN = -log(4 x 1 0^-10)= 9.3979
If we consider the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution
The weak acid for making the buffer must have a pKa value near to the desired pH of the weak acid.
So, near to value, pH=7.0. , the only option is HOCl whose pKa value is 7.45.
Hence, HOCl will be chosen for buffer construction.
