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Evgen [1.6K]
3 years ago
15

An element's ability to react with acid is an example of a

Chemistry
1 answer:
Dmitry [639]3 years ago
4 0

Answer:

it's chemical property

Explanation:

i took quiz

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Pls help
Simora [160]

Heat required to raise the temperature = 159.505 J

<h3>Further explanation</h3>

Given

c = specific heat of Beryllium = 1.825 J/g C

m = mass = 2.3 g

Δt = Temperature difference : 60 - 22 = 38 °C

Required

Heat required

Solution

Heat can be formulated

Q = m.c.Δt

Input the value :

Q = 2.3 x 1.825 x 38

Q = 159.505 J

8 0
2 years ago
8. How much enthalpy/heat is transferred when 0.5113
Gennadij [26K]
First convert to moles:
0.5113 g / 17 g/mol = 0.0301 mol

Now create a ratio based on the reaction provided to solve for the unknown:

4 NH3 / -905.4 kJ = 0.0301 mol NH3 / x kJ
x = -6.808 kJ
8 0
3 years ago
Which of the following compounds contains the Lead (II) ion?<br> PbO<br> PbCl4<br> Pb2O<br> Pb2S
KATRIN_1 [288]
<span>PbO Let's look at each of the 4 compounds and see what's needed. PbO. * Oxygen has a valance shell that's missing 2 electrons and wants to get those 2 elections. Lead donates them, so you have a Lead (II) ions. This is a correct choice. PbCl4 * Chlorine wants to grab 1 electron to fill it's valance shell and Lead donates that election. However, there's 4 chlorine atoms and every one of them wants and electron, and lead is donating all 4 of the desired electrons making the Lead (IV) ion. So this is a bad choice. Pb2O * Oxygen still wants 2 electrons and gets them from the lead. But there's 2 lead atoms and each of them donates 1 election making for 2 Lead(I) ions. So this too is a bad choice. Pb2S * Sulfur is in the same column of the periodic table as oxygen and if this compound were to exist would have similar properties as Pb2O and would have Lead(I) ions. So this is a bad choice.</span>
6 0
3 years ago
Read 2 more answers
Please Help!!!!!!!!!!!!!!!!!!!!
Alekssandra [29.7K]

Answer: first one

Explanation:

5 0
3 years ago
Read 2 more answers
A chemistry student needs 60.0 g of tetrahydrofuran for an experiment. By consulting the CRC Handbook of Chemistry and Physics,
Evgen [1.6K]

Answer:

67.492cm^3

Explanation:

To get the volume of tetrahydrofuran needed, what the student need to do is to apply mathematical calculations.

We know quite well that to obtain the volume of a substance, given the mass of the substance and the density of the substance is possible.

The volume of the substance is simply the mass of the substance divided by the density of the substance.

This is thus volume = mass/density

The mass given is the question is 60g while the density given is 0.889g/cm^3

The volume = 60/0.889 = 67.492cm^3

8 0
3 years ago
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