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3 years ago

What element is in the 3 rd period and 7th family

2 answers:

Nutka1998 [239]3 years ago

5 0

It is chlorine ( Cl ). Periods are rows in the table while families/groups are columns in the table.

P.S. I assume your asking about the VII.A group ( not the UK format )

aleksley [76]3 years ago

4 0

Pokémon is it that's the anwser

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When you apply 1000 joules of energy to 50 grams of water its temperature changes to 30 degrees . What was the initial temperatu

expeople1 [14]

Answer:

25.2°C

Explanation:

Given parameters:

Energy applied to the water = 1000J

Mass of water = 50g

Final temperature = 30°C

Unknown:

Initial temperature = ?

Solution:

To solve this problem, we use the expression below:

H = m c Ф

H is the energy absorbed

m is the mass

c is the specific heat capacity

Ф is the change in temperature

1000 = 50 x 4.184 x (30 - initial temperature )

1000 = 209.2(30 - initial temperature)

4.78 = 30 - initial temperature

4.78 - 30 = - initial temperature

Initial temperature = 25.2°C

7 0

3 years ago

A flash contains 85.6g of C7H5NO3S (Saccharine) in 2.00 litre of a solution. What is the molarity?

larisa86 [58]

Answer:

0.234 M

Explanation:

C- 12.009 x 7

H- 1.001 x 5

N- 14.006

O- 16 x 3

S- 32.059

___________+

183.133 g/mol

$\frac{1mol}{183.133g} *\frac{85.6g}{2.00L}$ = 0.234 M Cancel out the grams mol/L equals molarity. Lowest significant figure is 3

7 0

3 years ago

What is the volume of a gas if 0.182 moles of the gas is at 1.99 atm and 83.4oC?

Sunny_sXe [5.5K]

Answer:

2,67 L

Explanation:

8 0

2 years ago

How is ozone produced?

zubka84 [21]

The answer is A. the solar ultraviolet ray breaks the molecule apart

3 0

3 years ago

Read 2 more answers

What is the mass of 3.77mol of K3N?

AleksAgata [21]

<h3>Answer:</h3>

495 g K₃N

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.77 mol K₃N

<u>Step 2: Identify Conversions</u>

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of K₃N - 3(39.10) + 14.01 = 131.31 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 3.77 \ mol \ K_3N(\frac{131.31 \ g \ K_3N}{1 \ mol \ K_3N})$
Multiply/Divide: $\displaystyle 495.039 \ g \ K_3N$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

495.039 g K₃N ≈ 495 g K₃N

5 0

3 years ago