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MatroZZZ [7]
2 years ago
15

Questions for buffers lab, please help.

Chemistry
1 answer:
TEA [102]2 years ago
4 0

Answer:

because the acid properties of aspirin may be problematic.

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What mass of magnesium oxide is produced when 60g of magnesium is burnt in air?
True [87]

Answer:

The chemical equation can be written as:

2Mg+O

2

→2MgO

48 g of Mg reacts with 32 g of O

2

.

Thus, 4.8 g of Mg reacts with 3.2 g of O

2

.

Now, 32 g of O

2

forms = 80 g of MgO.

3.2 g of O

2

produces =

32

80

×3.2 = 8 g of MgO.

Was this answer helpful?

MARK ME AS BRAINLIEST

3 0
3 years ago
How are ionic bonds formed?
lisov135 [29]

Answer:

D

Explanation:

It occurs when the outermost electrons are permanently transferred to another atom.

7 0
3 years ago
At the end of a reaction it is important to remove the solvent from a solid product (more than one answer may be correct):
vova2212 [387]

Answer:

(B.) and (C.)

b. So that clean NMR spectra can be obtained that do not contain solvent peaks.

c. So that the yield can be determined.

Explanation:

The solvent used in Nuclear Magnetic Resonance (NMR) spectrometer is Trimethyl silane (TMS), a neutral solvent which doesn't give off any signals. Other solvents could have interactions with the radiation, and disrupt the spectra.

Furthermore, for accurate determination of the actual yield and overall percentage yield, solid must be separated from the solvent, dried and weighed.

I hope this was explanatory enough.

7 0
3 years ago
Convert this temperature from F to C<br><br> 26.6°c<br> 93.600<br> 62.2°C<br> 5.7°C
eduard
The answer for this is 26.6°c
3 0
3 years ago
Easy Chem, Will Give brainliest
Crazy boy [7]

Answer:

3.94 L

Explanation:

From the question given above, the following data were obtained:

Mass of O₂ = 5.62 g

Volume of O₂ =?

Next, we shall determine the number of mole present in 5.62 g of O₂. This can be obtained as follow:

Mass of O₂ = 5.62 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mole of O₂ =?

Mole = mass / molar mass

Mole of O₂ = 5.62 / 32

Mole of O₂ = 0.176 mole

Finally, we shall determine the volume of 5.62 g (i.e 0.176 mole) of O₂ at STP. This can be obtained as follow:

1 mole of O₂ occupied 22.4 L at STP.

Therefore, 0.176 mole of O₂ will occupy = 0.176 × 22.4 = 3.94 L at STP.

Thus 5.62 g (i.e 0.176 mole) of O₂ occupied 3.94 L at STP

5 0
3 years ago
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