KCIO3 → KCI + O2

First you have to count all the atoms of each element in both sides of the reaction, in this case:
Left side: there is one K atom, one Cl atom and 3 O atoms
Right side: there is one K atom, one Cl atom and 2 O atoms

K and Cl are balanced but O isn't
To balance O you can add a coefficient to O2 in the right side of the equation like this:

KCIO3 → KCI +3 O2

Now you have 6 oxygen atoms in the right side but only 3 in the left side, so you can add a coefficient to KClO3:

2KCIO3 → KCI +3 O2

And finally, Balance K and Cl again by adding a 2 as a coefficient for KCl

2KCIO3 → 2KCI +3 O2

Now both sides have the same amount of atoms of each element (2 K atoms, 2 Cl atoms and 6 O atoms)

8 0

4 years ago

11.

grin007 [14]

Applying the conservation of mass:

Mass during bombardment:
242 (curium atom) + 4 (alpha particle)
= 246

This must equal the mass after bombardment:
1 (neutron) + x (unknown product)

246 = 1 + x
x = 245

The product is Californium-245

6 0

3 years ago

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