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ioda
3 years ago
6

Which formula equation represents the burning of sulfur to produce sulfur dioxide?

Chemistry
1 answer:
Ghella [55]3 years ago
8 0

Answer:

O S(s) + O2(9) A, 502(9)

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A patient needs 40.0 mg of antibiotic per kilogram of body weight each day. If the patient weighs 55 kilograms.
White raven [17]

2200 mg of antibiotic

Explanation:

Given that 40 mg of antibiotic/kg of the bodyweight is given.

If patient is 55 kg then  the dose of antibiotic will be

if 40/1000000 is done then we can get antibiotic in kg/kg of the weight

= 0.00004 kg of antibiotic per kg

0.00004*55 ( to know how much 55 kg person will require)

= 0.0022 kg

This 0.0022 value will be converted to mg

0.0022*10^6

= 2200 mg of antibiotic will be given to a 55kg patient.

4 0
3 years ago
A student assisting with the experiment would observe all of the following about the electron transport chain EXCEPT:A. Electron
zheka24 [161]

Answer:

C. All electron carriers are mobile and hydrophobic

Explanation:

Hello,

In this case, it is widely known that the electron carriers move inside the inner mitochondrial membrane and consequently move electrons from one to another. In such a way, they are mobile, therefore they are largely hydrophobic as long as they are inside the membrane.

For instance, the cytochrome c is a water-soluble protein in a large range, therefore, the answer is: C. All electron carriers are mobile and hydrophobic.

Best regards.

5 0
3 years ago
In order to prepare very dilute solutions, a lab technician chooses to perform a series of dilutions instead of measuring a very
laiz [17]

Answerit is a

Explanation:

8 0
3 years ago
How many moles are in 1.05 g of gold (Au)?
Wittaler [7]

Answer:

0.005 mol

Explanation:

Moles is denoted by given mass divided by the molecular mass ,  

Hence ,  

n = w / m

n = moles ,  

w = given mass ,  

m = molecular mass .

From the question ,

w = given mass of Gold = 1.05 g ,

m = molecular mass of Gold = 197 g/mol

<u>Hence , moles can be calculated as -</u>

n = w / m = 1.05 g / 197 g/mol = 0.005 mol

7 0
3 years ago
A 7.12 L cylinder contains 1.21 mol of gas A and 4.94 mol of gas B, at a temperature of 28.1 °C. Calculate the partial pressure
GenaCL600 [577]

Answer:

P_A=4.20atm\\\\P_B=17.1atm

Explanation:

Hello!

In this case, since the equation for the ideal gas is:

PV=nRT

For each gas, given the total volume, temperature (28.1+273.15=301.25K) and moles, we can easily compute the partial pressure as shown below:

P_A=\frac{n_ART}{V} =\frac{1.21mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_A=4.20atm\\\\P_B=\frac{n_BRT}{V} =\frac{4.94mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_B=17.1atm

Best regards!

8 0
3 years ago
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