second compound
Let molar mass of x is = X
Let molar mass of y is = Y
Moles of x in second compound = Mass / molar mass = 7 / X
Moles of y in second compound = Mass / molar mass = 4.5 / Y
For second compound
7 / X : 4.5/ Y = 1:1
Therefore
X / Y = 7/4.5
Y / X = 4.5/ 7
The mass of x in first compound = 14g
moles of x in first compound = 14/X
Mass of y in first compound = 3
moles of y in first compound = 3 / Y
14 / X : 3/ Y = 14Y / 3X = 14 X 4.5 / 3 X 7 = 3 :1
Thus molar ratio in first compound = moles of x / Moles of y = 3:2
Formula = x3y
Explanation:
The given reaction is as follows.
![E + S \rightleftharpoons ES \xrightarrow[]{k_{2}} E + P](https://tex.z-dn.net/?f=E%20%2B%20S%20%5Crightleftharpoons%20ES%20%5Cxrightarrow%5B%5D%7Bk_%7B2%7D%7D%20E%20%2B%20P)
Here, [E] = triose phosphate isomerase = 0.1 
[S] = Dihydroxy acetone phosphate = 5 
[P] = Glyceraldehyde-3-phosphate = 2 
Therefore, velocity of the reaction will be as follows.
v =
= ![\frac{K_{2}[E][S]}{K_{M} + [S]}](https://tex.z-dn.net/?f=%5Cfrac%7BK_%7B2%7D%5BE%5D%5BS%5D%7D%7BK_%7BM%7D%20%2B%20%5BS%5D%7D)
where,
= Michaelic menten constant = 
v = 
= 
or, = 30 nm/s
Hence, we can conclude that the actual velocity of the forward reaction under physiologic conditions if KM = 10 μM is 30 nm/s.
Answer:
a colloid and a solution
Explanation:
When solute particles completely dissolve in a solvent, a true solution is formed. The solute particles in this case are so little that they can not be seen with naked eyes. A true solution does not scatter rays of light.
In a false solution, the solute particles are larger than the solute particles in true solutions but are not large enough to be seen with naked eyes. False solutions scatter rays of light. False solutions are also called colloids.
The major difference between a solution and a colloid is that colloids scatter light rays (Tyndall effect) while a true solution does not scatter light rays.
Answer:
The heating and melting of wax
Explanation:
When a candle is burned the wax heats up, but when cooled it hardens and cannot be put back into it original form.
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