Answer: The SI unit of force is the newton, symbol N.
Explanation:
Answer:
16.68 m/s
Explanation:
The following data were obtained from the question:
Height (h) = 14.2 m
Initial Velocity (u) = 0 m/s
Final velocity (v) =?
Thus, the velocity (v) with which the ball hit the ground can be obtained as follow:
v² = u² + 2gh
NOTE: the acceleration due to gravity (g) = 9.8 m/s²
v² = u² + 2gh
v² = 0² + 2 × 9.8 × 14.2
v² = 0 + 278.32
v² = 278.32
Take the square root of both side
v = √278.32
v = 16.68 m/s
Therefore, the velocity with which the ball hit the ground is 16.68 m/s
Answer:- 0.273 kg
Solution:- A double replacement reaction takes place. The balanced equation is:
We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.
= 63.8 g aluminum nitrate
From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.
We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.
=
sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate and then the grams are converted to kg.
= 0.273 kg
So, 0.273 kg of 35% m/m sodium chlorate solution are required.
The statement which is true is
metals lose electrons to become cations
<u><em>Explanation</em></u>
- metals tends to loss electrons to attain noble gas electrons configuration.
- When metal loses electrons they form a positive charged ions.
- The positively charged ion is known as cations.
- for example sodium metal (Na) loses 1 electron to form a cation with a charge of positive 1 ( Na^+)