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madreJ [45]
3 years ago
13

A contains 2.60g of impure h2so4 in 5oocm³ of a solution 5.30g of na2co3 in 1.00dm³ of solution

Chemistry
1 answer:
Tatiana [17]3 years ago
3 0

Answer: a. 0.05mol/dm3

bi. 0.045mol/dm3

bii. 4.41g/dm3

c. 84.8%

Explanation:Please see attachment for explanation

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If 42.8 mL of 0.204 M HCl solution is needed to neutralize a solution of Ca(OH)2, how many grams of Ca(OH)2 must be in the solut
Aneli [31]

Hey There!

At neutralisation moles of H⁺ from HCl  = moles of OH⁻ from Ca(OH)2  so :

0.204 * 42.8 / 1000  => 0.0087312 moles

Moles of Ca(OH)2 :

2 HCl + Ca(OH)2 = CaCl2 + 2 H2O

0.0087312 / 2 => 0.0043656 moles (  since each Ca(OH)2 ives 2 OH⁻ ions )

Therefore:

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Hope that helps!

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