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Vika [28.1K]
3 years ago
14

Does a change of phase produce a new substance? Explain. Please help me on this ❤

Chemistry
1 answer:
Brums [2.3K]3 years ago
3 0
Liquid, solid, and gas are all different substances
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Calculate the lattice energy for NaF (s) given the following
san4es73 [151]

Answer: E

Explanation:

The lattice energy is the energy change when one mole of a crystal is formed from its components ions in its gaseous sate

Therefore lattice energy = heat of Sublimation+ ionization energy +electron affinity-(heat of formation)

Therefore lattice Energy =     109 +495 -328 +570.

Lattice energy = --923kjmol-1

3 0
3 years ago
What is the solubility of CaCl2 at 20°C
slavikrds [6]

Answer:1,01

Explanation:

3 0
2 years ago
PH of 0,035M HCl? How to count if your calculator hasn't got -lg?
IrinaK [193]

<u>Given information:</u>

Concentration of HCl = 0.035 M

<u>To determine:</u>

pH of the solution

<u>Explanation:</u>

Hydrochloric acid, HCl is a strong acid. It will completely dissociate to give H+ and Cl- ions

HCl → H+ + Cl-

Hence the concentration of H+ = Cl- = 0.035M

Now, pH measures the strength of H+ ions in a given solution. It is expressed as:

pH = -log[H+]

pH (HCl) = -log(0.035) = 1.46

Ans: pH of 0.035M HCl is 1.46

6 0
2 years ago
How many atoms in 5.01 mole of lead?
leva [86]

Answer:

30.17 × 10²³ atoms

Explanation:

Given data:

Number of moles of lead = 5.01 mol

Number of atoms = ?

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

In given question:

1 mole = 6.022 × 10²³ atoms

5.01 mol × 6.022 × 10²³ atoms / 1 mol

30.17 × 10²³ atoms

3 0
2 years ago
A nuclear fission reaction has mass difference between the products and the reactants of 0.0284 amu. Calculate the
notsponge [240]

Answer:

C) 4.24 x 10^{-12}

Explanation:

E = Δmc^{2}

Δm = 0.0284 x 1.66 x 10^{-27} kg = 4.714x10^{-29}kg

putting value in above equation

E = 4.714x10^{-29}kg x (3x10^{8})^{2} = 4.24 x 10^{-12}

6 0
2 years ago
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