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Lostsunrise [7]
3 years ago
12

If 1495 J of heat is needed to raise the temperature of a 319 g sample of a metal from 55.0°C to 66.0°C, what is the specific he

at capacity of the metal?
Chemistry
1 answer:
Olegator [25]3 years ago
3 0
The specific  heat  capacity  of the  metal  is calculated  using  the  following  formula
Q(heat)= MC delta T
Q= 1495 j
c= specific heat   capacity =?
M(mass)=319 g
delta T = change  in  temperature = 66-55 =11 c
by  making   c  the subject  of the formula 

  C=Q /M delta T
c= 1495 j/ 319 g  x 11 c =0.426 j/g/c

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3 years ago
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Sveta_85 [38]

Answer:

4.0 moles

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Pressure = 5.6 atm

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2 years ago
If the molar absorptivity constant for the red dye solution is 5.56×104 M-1cm-1, calculate the molarity of the red dye solution
Shtirlitz [24]

Explanation:

a) Using Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

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A = absorbance of solution = 0.945

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\epsilon = molar absorptivity of this solution =5.56\times 10^4 M^{-1} cm^{-1}

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c) In order to dilute red dye solution by 5 times, we will need to add 1 L of water to solution of given concentration.

Concentration of red dye solution = c=1.4163\times 10^{-5} M

Concentration of red solution after dilution = c'

c=c'\times 5

1.4163\times 10^{-5} M=c'\times 5

c'=2.83\times 10^{-6} M

The final concentration of the diluted solution is 2.83\times 10^{-6} M

8 0
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