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mrs_skeptik [129]
1 year ago
7

At 3:00 PM a man 138 cm tall casts a shadow 149 cm long. At the same time, a tall building nearby casts a shadow 163 m long. How

tall is the building?
Mathematics
1 answer:
Andre45 [30]1 year ago
7 0

The building is 151 meters tall

<h3>How to determine the height of the building?</h3>

From the question, we have the following parameters about the building and the man

Man's height = 138 cm

Man's shadow = 149 cm

Building's shadow = 163 m

Based on the above parameters, we have the following equivalent ratio:

Ratio = Height : Shadow

So, we have:

Man's height : Man's shadow = Building's height : Building's shadow

Substitute the known values in the above equation

138 cm : 149 cm = Building's height : 163 m

Remove the units

138 : 149 = Building's height : 163

Express as fraction

138 /149 = Building's height/163

Multiply both sides by 163

Building's height = 163 * 138 /149

Evaluate the product

Building's height = 151 m

Hence, the building is 151 meters tall

So, the complete parameters are:

Man's height = 138 cm

Man's shadow = 149 cm

Building's shadow = 163 m

Building's height = 151 m

Read more about similar shapes at:

brainly.com/question/14285697

#SPJ1

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Hey there! :)

Answer:

x = 21 units.

Step-by-step explanation:

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\frac{45}{35}= \frac{27}{x}

Cross multiply to solve for x:

45 · x = 35 · 27

45x = 945

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x = 21 units.

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3 years ago
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Answer:

312.38

Step-by-step explanation:

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Is x + 10 a factor of the function f(x) = x3 − 75x + 250? Explain.
PtichkaEL [24]
Yes. When the function f(x) = x3 – 75x + 250 is divided by x + 10, the remainder is zero. Therefore, x + 10 is a factor of f(x) = x3 – 75x + 250. 

According to the remainder theorem when f(x) is divided by (x+a) the remainder is f(-a). 
In this case, 
f(x)=x^3-75x+250 
(x+a)=(x+10) 
Therefore, the remainder f(-a)=f(-10) 

=x^3-75x+250 
=(-10)^3-(75*-10)+250 
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The remainder is 0. So, (x+10) is a factor of x^3-75x+250.
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3 years ago
A recipe needs ½ cup of chocolate chips for each ¾ cup of sugar. How many cups of sugar are needed for each cup of chocolate chi
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Suppose each of the following data sets is a simple random sample from some population. For each dataset, make a normal QQ plot.
adell [148]

Answer:

a) For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

b) For this case the data is skewed to the left and we can't assume that we have the normality assumption.

c) This last case the histogram is not symmetrical and the data seems to be skewed.

Step-by-step explanation:

For this case we have the following data:

(a)data = c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

We can use the following R code to get the histogram

> x1<-c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

> hist(x1,main="Histogram a)")

The result is on the first figure attached.

For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

(b)data = c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> x2<- c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> hist(x2,main="Histogram b)")

The result is on the first figure attached.

For this case the data is skewed to the left and we can't assume that we have the normality assumption.

(c)data = c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> x3<-c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> hist(x3,main="Histogram c)")

The result is on the first figure attached.

This last case the histogram is not symmetrical and the data seems to be skewed.

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