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4 years ago

Write the algebraic expression for the quotient of 79 and x

1 answer:

3 0

79/x is the expression, though you cannot effectively find an answer to this without having an integer substitution for x.

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Solve for b. -1b - 8 > -7

kondor19780726 [428]

Step-by-step explanation:

Hey there!

Given;

-1b - 8 > -7

Take '-8' to right side.

-1b > -7+8

-1b > 1

b > -1

<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0

3 years ago

What is the factored form of x^2 - 196 ?

Luba_88 [7]

D. (x-14)(x+14)
a negative and a positive multiplied makes a negative outcome so -14•+14=-196. x•x is = to x^2

8 0

4 years ago

Read 2 more answers

a jeweler buys a ring from a jewelry maker for $125 he make up the price by 135% for sale in a store what is the selling price o

lidiya [134]

125 x 1.35= $168.75
168.75 + (168.75 x 0.075)= $181.41

6 0

3 years ago

Can someone please help and explain its due in a littleee

jek_recluse [69]

$f(x) = {x}^{2} - 3x + 2$

put x = (-1)

$f( - 1) = {( - 1)}^{2} - 3 \times ( - 1) + 2 \\ \\ 1 + 3 + 2 \\ \\ 6.$

put x = (z)

$f(z) = {z}^{2} - 3 \times z + 2 \\ \\ {z}^{2} - 3z + 2 \\ \\ {z}^{2} - 2z - z + 2 \\ \\ z(z - 2) - 1(z - 2) \\ \\ (z - 1)( z -2 ) \\ \\ (z - 1) = 0 \: \: , \: \: (z - 2) = 0\\ \\ z = 1 \:, \: 2$

put x = (x+1)

$f(x + 1) = {x}^{2} - 3x + 2 \\ \\ {(x + 1)}^{2} - 3 (x + 1) + 2 \\ \\ {x}^{2} + 1 + 2x - 3x - 3 + 2 \\ \\ {x}^{2} - x \\ \\ x(x - 1) \\ \\ x(x - 1) = 0 \\ \\ x - 1 = \frac{0}{x} \\ \\ x - 1 = 0 \\ \\ x = 1.$

put x = (√2 + 1 )

$f( \sqrt{2} + 1) = {x}^{2} - 3x + 2 \\ \\ {( \sqrt{2} + 1) }^{2} - 3( \sqrt{2} + 1) + 2 \\ \\ 2 + 1 + 2\sqrt{2} - 3 \sqrt{2} - 3 + 2 \\ \\ 3 - 1 \sqrt{2} - 1 \\ \\ 2 - \sqrt{2} \\ \\ 2 - 1.4 (optional \: \: \: steps)\\ \\ 0.6 \: \:$

4 0

2 years ago

HELPPP ASAPPP!!!!!!!!!!

Veronika [31]

Answer:

Step-by-step explanation:

3 0

3 years ago