1. What is the object’s average speed during the time interval from 1 s to 3 s?
1 answer:
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This question is incomplete, the microstates table is left out which will be uploaded along this answer;
Answer:
a) the required is 65.6%
b) the required time is 4.2666 hrs
Step-by-step explanation:
using the microstates from the table in the diagram;
a)
the percent times the above any of the above microstates occurs is;
% (6 heads and 4 tails, 5 heads and 5 tails, 4 heads and 6 tails)
= ((210 + 252 + 210)/1024) × 100
= 0.6562 × 100
= 65.6%
Therefore the required is 65.6%
b)
the probability of getting 10 heads and 0 tail or 0 tail head and 10 tails is;
p( 10H, 0T or 0H, 10T = 2/1024
= 1/512
so on average, it will take 512 trails or at a rate of 2 trials/min, 256 mim in hours;
(256 min) ( 1h/60min) = 4.2666 hrs
Therefore the required time is 4.2666 hrs
