Answer:
B) carbon dioxide and water
Answer:
0.294 M
Explanation:
The computation of the final molarity of acetate anion is shown below:-
Lead acetate = Pb(OAc)2
Lead acetate involves two acetate ion.
14.3 gm lead acetate = Mass ÷ Molar mass
= 14.3 g ÷ 325.29 g/mol
= 0.044 mole
Volume of solution = 300 ml.
then
Molarity of lead is
= 0.044 × 1,000 ÷ 300
= 0.147 M
Therefore the molarity of acetate anion is
= 2 × 0.147
= 0.294 M
Answer:
Q_d=35881 J/mol
So the activation energy is 35881 J/mol.
Explanation:
Consider the following equations:
Solving the above two equation to find the Q_d in term of diffusivity and temperature we will get:
where:
Q_d is the activation energy
D_1 is the diffusivity at T_1
D_2 is the diffusivity at T_2
Q_d=35881 J/mol
So the activation energy is 35881 J/mol.
Diffusion if the movement of small molecules across the cell membrane.
Kinetic energy of the molecules results in random motion, causing diffusion.
