Answer:
Well ads I remember, the motion of the gas particles is random and in a straight-line. A sample of gas is contained in a closed rigid cylinder.
And here is what I found too -
According to Kinetic Molecular Theory, gaseous particles are in a state of constant random motion; individual particles move at different speeds, constantly colliding and changing directions. We use velocity to describe the movement of gas particles, thereby taking into account both speed and direction.
Answer:
the reactants are 2h2 and 02. the products are 2h20
have a great day my friend ;)
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Answer:
D. They have the same number of protons as electrons.
Explanation:
Protons are found in the nucleus of the atom and have a positive charge while electrons orbit around the nucleus and have a negative charge. Usually, in a neutral atom of an element, the number of protons is equal to the number of electrons. This is why the atom has no charge because the positive and negative charges cancel out. When an atom loses an electron its charge turns positive while when it gains an electron its charge turns negative.
The pKa of the dimethylammonium ion, (CH₃)₂NH₂⁺ is 10.7.
<h3>
What do we know about dimethylammonium ion?</h3>
The conjugate acid of dimethylamine, dimethylaminium is an organic cation and a significant species at pH 7.3. It is a secondary aliphatic ammonium ion and an organic cation. It is a dimethylamine conjugate acid.
<h3>What do we understand by pKa?</h3>
In layman's terms, pKa is a measurement of an acid's strength. A strong acid will have a pKa value that is lower than 0. To be more specific, pKa is the Ka value's negative log base ten value (acid dissociation constant). How tightly a proton is retained by a Bronsted acid is how the strength of an acid is measured. The strength of the acid and its capacity to donate protons increase with decreasing pKa values.
To learn more about pKa:
brainly.com/question/13178964
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For Number 2 It Is The Law Of Conversation Of Mass
Number 3 Atoms Of Each Element
Number 7 Oxygen
Number 5 Single Replacement Reaction
I answered a few of them