A. p block
from 3a-8a are in the p block including halogen
1) we find out the volume of the water.
Remember: 1 ml=1 cm³
Volume of the water=number of cups x volume of one cup.
Volume of the water=2.5(240 ml)=600 ml=600 cm³
Density=mass/volume ⇒ mass=density x volume
2) we calculate the water mass of 600 cm³ of water.
mass=density x volume
mass=(1 g/cm³)(600 cm³)=600 g.
Answer: the mass of 2.5 cupas of water is 600 g.
<em>Maybe</em>
<em>Mg+</em><em>Fe2O3</em><em>→</em><em>F</em><em>e</em><em>+</em><em>MgO</em>
<em>hope</em><em> it</em><em> helps</em>
Answer:
Colloidal dispersion or emulsion
Explanation:
The colloid of a liquid in liquid (both dispersed phase and dispersion medium are liquids) is known as emulsion or colloidal dispersion.
We know that oil and water are immiscible liquids. In order to make them miscible we have have add emulsifying agents.
An emulsifying agent has a long non polar hydrocarbon chain (in general) and a polar head.
For example salts of fatty acids.
The polar head is hydrophilic and non polar tail is hydrophobic.
It causes the miscibility of the two polar and non polar liquids
<u>Answer:</u> The nuclear equation for the conversion of He-3 nuclide to He-4 nuclide is given above.
<u>Explanation:</u>
Nuclear reaction are defined as the reactions in which nucleus of an atom is involved.
Positron emission is defined as the emission process in which positron particle is emitted. In this process, a proton gets converted to neutron and an electron neutrino particle.
The chemical equation for the reaction of He-3 with a proton follows:
Hence, the nuclear equation for the conversion of He-3 nuclide to He-4 nuclide is given above.
