Question

A student receives 83.2 points, 44.6 points, 74.4 points, and 52.3 points on each of four tests. Determine the student’s test average with the correct significant digits.

Answer 1

Answer:

Average = 63.6

Explanation:

Average : The average of the given set of points can be calculated by dividing sum of the total point to the number of points.

$Average =\frac{Sum\ of\ points}{Number\ of\ points}$

The points that are given in this equation are:

83.2 , 44.6 , 74.4 , 52.3 .

These are 4 in number . So average is

$Average =\frac{Sum\ of\ points}{Number\ of\ points}$

$Average =\frac{83.2+44.6+74.4+52.3}{4}$

$Average =\frac{254.5}{4}$

$Average =63.625$

Significant digits : It is the number of digits that carry meaningful value to a measurement. The rules for counting number of significant digits are:

1. all non-zero digit are significant

2.Any zero between two non-zero are also significant.(305 = 3 significant digit )

3. Zero before the decimal are non-significant (0.003 = only 1 significant digit)

Zero after decimal are significant (3.00 has 3 significant digit)

4.Zero after non - zero digit is non significant (300 has 1 significant digit).

Significant digits in division :

The answer should have the significant digits that are least in any of number(83.2 , 44.6 , 74.4 , 52.3 )

All have = 3 significant digits.

So least numner of significant digit =3

Answer should have total = 3 significant digits

So,

Average = 63.6