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Aliun [14]
2 years ago
13

For typical rubber-on-concrete friction, what is the shortest time in which a car could accelerate from 0 to 70 mph? suppose tha

t μs=1. 00μs=1. 00 and μk=0. 80μk=0. 80
Physics
1 answer:
algol132 years ago
3 0

The shortest time in which a car could accelerate from 0 to 70 mph is 3.193 seconds.

To find the answer, we have to know more about the friction.

<h3>How to find the shortest time?</h3>
  • We have the expression for final velocity as,

                          v=u+at

  • It is given in the question that,

                        v=70mph=31.29m/s\\1mile=1609.3m,1hour=3600s\\u=0\\k_s=1\\k_k=0.8

  • It is given that; the car could accelerate from 0 to 70mph. Thus, acceleration will be,

                    a=g*k_s=9.8*1=9.8m/s^2

  • Thus, the shortest time will be,

                    t=\frac{v-u}{a} \\t=\frac{31.29}{9.8}=3.193s

Thus, we can conclude that, the shortest time in which a car could accelerate from 0 to 70 mph is 3.193 seconds.

Learn more about the shortest time here:

brainly.com/question/3017271

#SPJ4

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dsp73

Answer:

angular speed of both the children will be same

Explanation:

Rate of revolution of the merry go round is given as

f = 4.04 rev/min

so here we have

f = \frac{4.04}{60} =0.067 rev/s

here we know that angular frequency is given as

\omega = 2\pi f

\omega = 2\pi(0.067)

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An electron with a speed of 0.95c is emitted by a supernova, where cc is the speed of light. What is the magnitude of the moment
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Answer:

2.59×10¯²² Kgm/s

Explanation:

Data obtained from the question include:

Velocity of electron = 0.95c

Momentum =?

Next, we shall determine the velocity of the electron. This can be obtained as follow:

Velocity of electron = 0.95c

Velocity of Light (c) = 3×10⁸ m/s

Velocity of electron = 0.95c

Velocity of electron = 0.95 × 3×10⁸

Velocity of electron = 2.85×10⁸ m/s

Finally, we shall determine the mometum of the electron.

Momentum is simply defined as the product of mass and velocity. Mathematically, it is expressed as:

Momentum = mass x Velocity

Thus, with the above formula, we calculate the momentum of the electron as follow:

Mass of electron = 9.1×10¯³¹ Kg

Velocity of electron = 2.85×10⁸ m/s

Momentum of electron =?

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A baseball has a mass of 0.15 kg and radius 3.7 cm. In a baseball game, a pitcher throws the ball with a substantial spin so tha
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Answer:

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Explanation:

Rotational kinetic energy is given by

\text{RKE} = \frac{1}{2}I\omega^2

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