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melisa1 [442]
1 year ago
15

A car starts from rest and accelerates at 4 m/s2 until it reaches 36 m/s. How far did it travel in this time?

Physics
1 answer:
dexar [7]1 year ago
3 0

The distance of a car that starts from rest and accelerates at 4 m/s² until it reaches 36 m/s is 162m.

<h3>How to calculate distance?</h3>

The distance moved by a body can be calculated using the following formula:

S = ut + ½at²

Where;

  • S = distance
  • u = initial velocity
  • t = time
  • a = acceleration

However, the time taken for the car to complete the acceleration can be calculated as follows:

4 = 36/t

t = 9seconds

S = 0 × t + ½ × 4 × 9²

S = 0 + 162

S = 162m

Therefore, the distance of a car that starts from rest and accelerates at 4 m/s² until it reaches 36 m/s is 162m.

Learn more about distance at: brainly.com/question/15256256

#SPJ1

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You are planning to make an open rectangular box from an 8-inch by 15-inch piece of cardboard by cutting congruent squares from
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Let us say that x is the cut that we will make on the sides to make a box, therefore the new dimensions are:

l = 15 – 2x

w = 8 – 2x

It is 2x since we cut on two sides.

 

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V = l w x

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Taking the 1st derivative:

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Set dV/dx = 0 to get maxima:

120 – 92x + 12x^2 = 0

 

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(x – (92/24))^2 = -10 + (92/24)^2

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So the largest volume is:

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4 years ago
A plane drops a hamper of medical supplies from a height of 5000 m during a practice run over the ocean. The plane’s horizontal
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Answer:

346.70015 m/s

Explanation:

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v_x=149\ m/s

In the y axis

v_y=\sqrt{2gh}\\\Rightarrow v_y=\sqrt{2\times 9.8\times 5000}

The resultant velocity is given by

v=\sqrt{v_x^2+v_y^2}\\\Rightarrow v=\sqrt{149^2+2\times 9.8\times 5000}\\\Rightarrow v=346.70015\ m/s

The magnitude of the overall velocity of the hamper at the instant it strikes the surface of the ocean is 346.70015 m/s

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A rubber-wheeled 50 kg cart rolls down a 35 degree concrete incline. Coefficient of rolling friction between rubber and concrete
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Answer:

(a) 5.62 m/s²

(b) 5.46 m/s²

Explanation:

The given values are:

mass,

m = 50 kg

angle

= 35°

(a)

If friction neglected,

⇒ F_x=mgSin \theta=ma

⇒ a_x=gSin \theta

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(b)

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      =5.46 \ m/s^2

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