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1 year ago

A car starts from rest and accelerates at 4 m/s2 until it reaches 36 m/s. How far did it travel in this time?

Physics

1 answer:

dexar [7]1 year ago

3 0

The distance of a car that starts from rest and accelerates at 4 m/s² until it reaches 36 m/s is 162m.

<h3>How to calculate distance?</h3>

The distance moved by a body can be calculated using the following formula:

S = ut + ½at²

Where;

S = distance
u = initial velocity
t = time
a = acceleration

However, the time taken for the car to complete the acceleration can be calculated as follows:

4 = 36/t

t = 9seconds

S = 0 × t + ½ × 4 × 9²

S = 0 + 162

S = 162m

Therefore, the distance of a car that starts from rest and accelerates at 4 m/s² until it reaches 36 m/s is 162m.

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Explanation:

The y-component of the acceleration is given by

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$u_y$ is the y-component of the initial velocity

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For the ice skater in this problem, we have:

u = 2.25 m/s is the initial velocity, in a direction $\theta=50.0^{\circ}$

v = 4.65 m/s is the final velocity, in a direction $120^{\circ}$

t = 8.33 s is the time elapsed

The y-components of the initial and final velocity are:

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So the y-component of the acceleration is

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Answer:

Explanation:

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